The equation of the hyperbola with directrices at x = ±2 and foci at (5, 0) and (−5, 0) is 
<h3>How to determine the equation of the hyperbola?</h3>
The given parameters are:
- Directrices at x = ±2
- Foci at (5, 0) and (−5, 0)
The foci of a hyperbola are represented as:
Foci = (k ± c, h)
The center is:
Center = (h,k)
And the directrix is:
Directrix, x = h ± a²/c
By comparison, we have:
k ± c = ±5
h = 0
h ± a²/c = ±2
Substitute h = 0 in h ± a²/c = ±2
0 ± a²/c = ±2
This gives
a²/c = 2
Multiply both sides by c
a² = 2c
k ± c = ±5 means that:
k ± c = 0 ± 5
By comparison, we have:
k = 0 and c = 5
Substitute c = 5 in a² = 2c
a² = 2 * 5
a² = 10
Next, we calculate b using:
b² = c² - a²
This gives
b² = 5² - 10
Evaluate
b² = 15
The hyperbola is represented as:

So, we have:

Evaluate

Hence, the equation of the hyperbola is 
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1, 3/3, 420/420 why such a wierd qustion
Answer:
2/3 1/2 3/4 5/6
Step-by-step explanation:
anything that isnt 1/3 or equal to it is an answer
Answer:
I know this is not exactly what your looking for but if you make a line and put all the points from 4+3i to 6-2i then you can find the distance between them.
Step-by-step explanation:
I'm so sorry that I don't really know the answer
Pls forgive me
Answer:
The square root of 162 in its simplest form means to get the number 162 inside the radical √ as low as possible.
Here is how to do that! First we write the square root of 162 like this:
√162
The largest perfect square of the factors of 162 is 81. We can therefore convert √162 like this:
√81 × 2
Next, we separate the numbers inside the √ as such:
√81 × √2
√81 is a perfect square that equals 9. We can therefore put 9 outside the radical and get the final answer to square root of 162 in simplest radical form as follows:
9√2
Step-by-step explanation: