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Maslowich
3 years ago
9

The owner of a small restaurant bought 75 kilograms of rice. Each week, the restaurant uses 4.5 kilograms of rice. Function r(w)

gives the remaining amount of rice, in kilograms, as a function of the number of weeks since the restaurant owner bought the rice.
What is the initial value? r(0) =

How much rice after 6 weeks? r(6) =

How much rice after 12 weeks? r(12) =
Mathematics
1 answer:
Artist 52 [7]3 years ago
3 0

Answer:

48 , 21 , 75 - 4.5u

Step-by-step explanation:

The step is above!

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What is the area of the triangle?<br> 9 4 12
LUCKY_DIMON [66]

Answer:

  13.636

Step-by-step explanation:

The area can be found using Heron's formula:

  A = √(s(s-a)(s-b)(s-c))

where s=(a+b+c)/2.

For the given triangle, ...

  a=9, b=4, c=12, s=(9+4+12)/2 = 12.5

  A = √(12.5(3.5)(8.5)(0.5)) = √185.9375 ≈ 13.636

The area of the triangle is about 13.636 square units.

7 0
3 years ago
What is the absolute value of -3? <br> A. -3<br> B. 3
Leona [35]

Answer:

<h2>B. 3</h2>

Step-by-step explanation:

|a|=\left\{\begin{array}{ccc}a&if&a\geq0\\-a&if&a

Examples:

|3|=3\ because\ 3\geq0\\\\|-10|=-(-10)=10\ because\ -10

Your question:

|-3|=-(-3)=3\\\\|-3|=3

5 0
3 years ago
Solve √5r - 9 - 3 = √r +4-2
Mekhanik [1.2K]

Answer:

  r = 5

Step-by-step explanation:

Solving radical equations often results in extraneous solutions. These can be avoided by using a graphing calculator for the solution.

<h3>Graph</h3>

The attached shows that the value of r that makes both sides of the equation have the same value is r = 5.

<em>Check:</em>

  √(5·5 -9) -3 = √(5 +4) -2   ⇒   4 -3 = 3 -2 . . . true

<h3>Analytical solution</h3>

Solution of an equation like this is typically done by isolating the radical expressions, then squaring the equation.

We can add 3, square the equation, then isolate the radical and square again:

  \displaysyle \sqrt{5r-9}-3=\sqrt{r+4}-2\\\\\sqrt{5r-9}=\sqrt{r+4}+1\qquad\text{add 3}\\\\5r-9=(r+4)+2\sqrt{r+4}+1\qquad\text{square both sides}\\\\(4r-14)^2=4(r+4)\qquad\text{subtract $(r+5)$ and square again}\\\\16r^2-116r+180=0\qquad\text{rewrite in standard form}\\\\4(4r -9)(r -5) = 0\qquad\text{factor}\\\\r=\{\dfrac{9}{4},\ 5\}\qquad\text{solutions to the factored form}

Trying these values in the original equation, we get ...

  √((5(9/4) -9) -3 = √(9/4 +4) -2   ⇒   1.5 -3 = 2.5 -2 . . . . . false

  √(5(5) -9) -3 = √(5 +4) -2   ⇒   4 -3 = 3 -2 . . . . . true

The solution is r = 5.

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