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IRISSAK [1]
3 years ago
6

Working alone, it takes Trevon eight hours

Mathematics
1 answer:
TiliK225 [7]3 years ago
7 0

Answer

18.8 if they are picking 80 bushes and 9.4 if their

picking the forty bushes together

Step-by-step explanation:

You might be interested in
Marigold Industries collected $104,000 from customers in 2019. Of the amount collected, $24,400 was for services performed in 20
m_a_m_a [10]

Answer:

\text{Net accrual income}=\$31,600

Step-by-step explanation:

We have been given that Marigold Industries collected $104,000 from customers in 2019. Of the amount collected, $24,400 was for services performed in 2018. In addition, Marigold performed services worth $39,000 in 2019, which will not be collected until 2020.

Let us find revenue earned in 2019 by subtracting revenue earned from 2018 and adding revenue earned in 2019 to total revenue as:

\text{Revenue in 2019}=\$104,000-\$24,400+\$39,000

\text{Revenue in 2019}=\$118,600

Marigold Industries also paid $73,900 for expenses in 2019. Of the amount paid, $29,100 was for expenses incurred on account in 2018. In addition, Marigold incurred $42,200 of expenses in 2019, which will not be paid until 2020.

Now, we will find expenses in 2019 by subtracting expenses in 2018 and adding expenses in 2019 to total expenses as:

\text{Expenses in 2019}=\$73,900-\$29,100+\$42,200

\text{Expenses in 2019}=\$87,000

To find accrual net-income, we will subtract$87,000 from $118,600 as:

\text{Net accrual income}=\$118,600-\$87,000

\text{Net accrual income}=\$31,600

Therefore, the net accrual income for 2019 would be $31,600.

5 0
3 years ago
9000 is 10 times as much as?
Zanzabum

Answer:

900

Step-by-step explanation:

4 0
3 years ago
it cost $3.45 to buy 3/4 lb of chopped walnuts how much would it cost to purchase 7.2 lb of walnuts ​
andreev551 [17]

Answer:

Step-by-step explanation:

$33.12

you would divide 3.45 by 3 to get 1/4, which is 1.15, then multiply that by 4 to get the cost for one pound, which is 4.6. multiply 4.6 times 7.2 to get your answer of 33.12

5 0
3 years ago
An educational psychologist wishes to know the mean number of words a third grader can read per minute. She wants to make an est
MrRa [10]

Answer:

<em> 85% level of the confidence interval is</em>

<em>(26.337, 26.662)</em>

Step-by-step explanation:

<u><em>Explanation</em></u>:-

Given the size of the sample 'n' = 295

Mean of the sample x⁻ = 26.5

The Standard deviation of the Population = 2.7

85% level of the confidence interval is determined by

(x^{-} - Z_{0.15} \frac{S.D}{\sqrt{n} } , x^{-} + Z_{0.15} \frac{S.D}{\sqrt{n} })

Critical value Z₀.₁₅ = 1.036

<em> 85% level of the confidence interval is determined by</em>

(x^{-} - Z_{0.15} \frac{S.D}{\sqrt{n} } , x^{-} + Z_{0.15} \frac{S.D}{\sqrt{n} })

(26.9 -1.036 \frac{2.7}{\sqrt{295} } , 26.5 + 1.036 \frac{2.7}{\sqrt{295} })

( 26.5 - 0.1628 , 26.5+0.1628)

(26.3372,26.6628)

7 0
3 years ago
Help me plz ASAP help help pls
spayn [35]

Answer:

x\geq -8

Step-by-step explanation:

4 0
3 years ago
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