Answer:
The value x in the equation 50=14+x+7+2x-1 is 10
Step-by-step explanation:
Given that the length of one side of a triangle is 14 inches
Let a be the length of one side
Therefore a=14 inches
The length of second side in x+7 inches
Let b be the length of second side
b=x+7 inches.
The length of third side is 2x-1 inches
Let c be the length of third side
c=2x-1 inches
And perimeter of the triangle =50 inches
Perimeter of a triangle =a+b+c
Equation can be written as
50=14+x+7+2x-1
50=20+3x ( adding the like terms )
Rewritting as below
3x+20=50
3x+20-50=50-50
3x-30=0
3x-30+30=0+30
3x=30
Therefore x=10
The value of x is 10
NO.,the given measures can not be the lengths of the sides of a triangle
Step-by-step explanation
The sum of the lengths of any two sides of a triangle must be greater than the length of the third side.
so, Find the range for the measure of the third side of a triangle given the measures of two sides.
here given measures are 2,2,6
2+2 = 4 which is less than the third side 6
= 4 < 6
This not at all a triangle.
Hence, the given measures can not be the lengths of the sides of a triangle
0 hope this helps!!!!!!!!!
Answer:
Third one is correct because it says it must be more than 2 not 2 or more.
The one you choose would be like, it must be 2 or more.
Step-by-step explanation:
