Answer:
C. ∠SRT≅∠VTR and ∠STR≅∠VRT
Step-by-step explanation:
Given:
Quadrilateral is a parallelogram.
RS║VT; RT is an transversal line;
Hence By alternate interior angle property;
∠SRT≅∠VTR
∠STR≅∠VRT
Now in Δ VRT and Δ STR
∠SRT≅∠VTR (from above)
segment RT= Segment RT (common Segment for both triangles)
∠STR≅∠VRT (from above)
Now by ASA theorem;
Δ VRT ≅ Δ STR
Hence the answer is C. ∠SRT≅∠VTR and ∠STR≅∠VRT
<span>you have to take arctan(0) to find the value of theta.
tan^-1 (x)=theta </span>
Answer:
x = y²
Step-by-step explanation:
Given
x = 
and y = 
Note that
x = = × = y²
Thus x = y²
Answer:
x = 1 and y = 5
Step-by-step explanation:
Use substitution because you know that x = y - 4, and plug this into the first equation to get -10(y - 4) + 3y = 5, or -10y + 40 + 3y = 5. This is -7y = -35 so y = 5. Plug this into the 2nd equation to get that x = 1 and y = 5.
<em>Substitute x = 2 as we get</em>
<em>f(2) = -4(2)+4 = -8+4 = -4</em>
<em>Therefore, f(2) = -4</em>
