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Sindrei [870]
3 years ago
12

.The endpoints of AB are A(1,4) and B(6,-1).

Mathematics
1 answer:
Brums [2.3K]3 years ago
4 0

Answer:

5√2

Step-by-step explanation:

<u>Finding</u><u> </u><u>distance</u><u> </u><u>:</u><u>-</u><u> </u>

  • d = √{ ( 1 -6)² + (4+1)²}
  • d = √{ -5² + 5² }
  • d = √{ 25 + 25}
  • d = √50
  • d = 5√2
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6x+3(4x-2)=5(2x-8) the answer is -17/4 but can someone explain how to get that answer? plz help lol​
Sergeu [11.5K]

Answer:

<h2>x =  -  \frac{17}{4}</h2>

Step-by-step explanation:

6x + 3(4x - 2) = 5(2x - 8)

Expand the terms in the bracket and simplify

That's

6x + 12x  - 6 = 10x - 40 \\ 18x - 6 = 10x - 40

Using the subtraction property subtract 10x from both sides of the equation

18x - 10x - 6 = 10x - 10x - 40 \\ 8x - 6 =  - 40

<u>Add 6 to both sides of the equation</u>

8x + 6 - 6 =  - 40 + 6 \\ 8x =  - 34

<u>Divide both sides by 8</u>

\frac{8x}{8}  =  -  \frac{34}{8}

<u>Reduce the fraction with 2</u>

We have the final answer as

x =  -  \frac{17}{4}

Hope this helps you

7 0
3 years ago
A survey of 76 commercial airline flights of under 2 hours resulted in a sample average late time for a flight of 2.55 minutes.
nika2105 [10]

Answer:

The best point of estimate for the true mean is:

\hat \mu = \bar X = 2.55

2.55-1.96\frac{12}{\sqrt{76}}=-0.148    

2.55+1.96\frac{12}{\sqrt{76}}=5.248    

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

Step-by-step explanation:

Information given

\bar X=2.55 represent the sample mean for the late time for a flight

\mu population mean

\sigma=12 represent the population deviation

n=76 represent the sample size  

Confidence interval

The best point of estimate for the true mean is:

\hat \mu = \bar X = 2.55

The confidence interval for the true mean is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

The Confidence level given is 0.95 or 95%, th significance would be \alpha=0.05 and \alpha/2 =0.025. If we look in the normal distribution a quantile that accumulates 0.025 of the area on each tail we got z_{\alpha/2}=1.96

Replacing we got:

2.55-1.96\frac{12}{\sqrt{76}}=-0.148    

2.55+1.96\frac{12}{\sqrt{76}}=5.248    

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

7 0
3 years ago
Four friends want to take a vacation together, so each one gets a part-time job. Each person has 8 weeks to save $720 for the va
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Both friend A and C will save enough money in 8 weeks.
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75 students in a kindergarten. 40% of them can read. how many can read?
Paul [167]

Answer:

30

Step-by-step explanation:

75 times .40 = 30

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3 years ago
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Completion time (from start to finish) of a building remodeling project is normally distributed with a mean of 200 work-days and
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We should request a completion time of

223 work-days.
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