.The endpoints of AB are A(1,4) and B(6,-1).

6x+3(4x-2)=5(2x-8) the answer is -17/4 but can someone explain how to get that answer? plz help lol

Sergeu [11.5K]

Answer:

Step-by-step explanation:

$6x + 3(4x - 2) = 5(2x - 8)$

Expand the terms in the bracket and simplify

That's

$6x + 12x - 6 = 10x - 40 \\ 18x - 6 = 10x - 40$

Using the subtraction property subtract 10x from both sides of the equation

$18x - 10x - 6 = 10x - 10x - 40 \\ 8x - 6 = - 40$

<u>Add 6 to both sides of the equation</u>

$8x + 6 - 6 = - 40 + 6 \\ 8x = - 34$

<u>Divide both sides by 8</u>

$\frac{8x}{8} = - \frac{34}{8}$

<u>Reduce the fraction with 2</u>

We have the final answer as

$x = - \frac{17}{4}$

Hope this helps you

7 0

3 years ago

A survey of 76 commercial airline flights of under 2 hours resulted in a sample average late time for a flight of 2.55 minutes.

nika2105 [10]

Answer:

The best point of estimate for the true mean is:

$\hat \mu = \bar X = 2.55$

$2.55-1.96\frac{12}{\sqrt{76}}=-0.148$

$2.55+1.96\frac{12}{\sqrt{76}}=5.248$

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

Step-by-step explanation:

Information given

$\bar X=2.55$ represent the sample mean for the late time for a flight

$\mu$ population mean

$\sigma=12$ represent the population deviation

n=76 represent the sample size

Confidence interval

The best point of estimate for the true mean is:

$\hat \mu = \bar X = 2.55$

The confidence interval for the true mean is given by:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

The Confidence level given is 0.95 or 95%, th significance would be $\alpha=0.05$ and $\alpha/2 =0.025$ . If we look in the normal distribution a quantile that accumulates 0.025 of the area on each tail we got $z_{\alpha/2}=1.96$

Replacing we got:

$2.55-1.96\frac{12}{\sqrt{76}}=-0.148$

$2.55+1.96\frac{12}{\sqrt{76}}=5.248$

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

7 0

3 years ago

Four friends want to take a vacation together, so each one gets a part-time job. Each person has 8 weeks to save $720 for the va

san4es73 [151]

Both friend A and C will save enough money in 8 weeks.

6 0

3 years ago

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75 students in a kindergarten. 40% of them can read. how many can read?

Paul [167]

Answer:

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