All categories

3 years ago

What is the area of a square if the length is 4x-3

Mathematics

2 answers:

sveta [45]3 years ago

7 0

Answer:

The area of square in terms of x = 16x² -24x + 9

Step-by-step explanation:

It is stated in the question that the length of a square = 4x - 3

Formula to find the area of the square is

Area = length²

Area = ( 4x - 3 )²

by using ( a - b )² = a² + b² - 2ab

here a = 4x and b = -3

So,

(4x)² + (-3)² - 2(4x)(3)

16x² + 9 - 2(12x)

16x² + 9 - 24x

16x² -24x + 9

The area of square in terms of x = 16x² -24x + 9

(hope this helps can i plz have brainlist :D hehe)

frez [133]3 years ago

3 0

Answer:

The area of square in terms of x = 16x² -24x + 9

Step-by-step explanation:

It is stated in the question that the length of a square = 4x - 3

Formula to find the area of the square is

Area = length²

Area = ( 4x - 3 )²

by using ( a - b )² = a² + b² - 2ab

here a = 4x and b = -3

So,

(4x)² + (-3)² - 2(4x)(3)

16x² + 9 - 2(12x)

16x² + 9 - 24x

16x² -24x + 9

The area of square in terms of x = 16x² -24x + 9

You might be interested in

Pls let me know in 5 min or I’m dead

Kitty [74]

Answer:

( 0 , 4 )

Step-by-step explanation:

Your estimate is correct

4 0

3 years ago

Read 2 more answers

Evaluate the following expression when a = 5 and b = 6 3a +10b

Anni [7]

The answer is 75 I believe :)

6 0

3 years ago

The diagonals of kite KITE intersect at point P. If m A. 34° B. 46° C. 68° D. 92°

JulijaS [17]

Answer:

The diagonal of kite intersect at the point p is C. 68°

7 0

3 years ago

Write a word phrase for each algebraic expression 49+m

Oksanka [162]

Sarah had $49 dollars, plus the money her mom had.

3 0

4 years ago

Read 2 more answers

The length of a rectangle is 3 more than 3 times its width. The perimeter of the rectangle is 174 inches. What is the length of

saveliy_v [14]

Answer:

l = w + 3cm

l = w + 3cmp = 2l + 2w = 58cm

l = w + 3cmp = 2l + 2w = 58cm 

l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:

l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58

l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58⇒ 2w + 6 + 2w = 4w + 6 = 58

l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58⇒ 2w + 6 + 2w = 4w + 6 = 58⇒ 4w = 52 ⇒ w = 13

l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58⇒ 2w + 6 + 2w = 4w + 6 = 58⇒ 4w = 52 ⇒ w = 13 

l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58⇒ 2w + 6 + 2w = 4w + 6 = 58⇒ 4w = 52 ⇒ w = 13 Plug back in:

l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58⇒ 2w + 6 + 2w = 4w + 6 = 58⇒ 4w = 52 ⇒ w = 13 Plug back in:l = (13cm) + 3cm = 16cm

l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58⇒ 2w + 6 + 2w = 4w + 6 = 58⇒ 4w = 52 ⇒ w = 13 Plug back in:l = (13cm) + 3cm = 16cmStep-by-step explanation:

I hope this helps you.

5 0

3 years ago