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Vsevolod [243]
3 years ago
7

What is the area of a square if the length is 4x-3

Mathematics
2 answers:
sveta [45]3 years ago
7 0

Answer:

The area  of square in terms of x = 16x² -24x + 9  

Step-by-step explanation:  

It is stated in the question that the length of a square = 4x - 3  

Formula to find the area of the square is  

Area = length²

Area = ( 4x - 3 )²  

by using ( a - b )² = a² + b² - 2ab  

here a = 4x and b = -3  

So,  

(4x)² + (-3)² - 2(4x)(3)  

16x² + 9 - 2(12x)  

16x² + 9 - 24x  

16x² -24x + 9

 

The area  of square in terms of x = 16x² -24x + 9

(hope this helps can i plz have brainlist :D hehe)

frez [133]3 years ago
3 0

Answer:

The area  of square in terms of x = 16x² -24x + 9

Step-by-step explanation:

It is stated in the question that the length of a square = 4x - 3

Formula to find the area of the square is

Area = length²

Area = ( 4x - 3 )²

by using ( a - b )² = a² + b² - 2ab

here a = 4x and b = -3

So,

(4x)² + (-3)² - 2(4x)(3)

16x² + 9 - 2(12x)

16x² + 9 - 24x

16x² -24x + 9

The area  of square in terms of x = 16x² -24x + 9

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3 years ago
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A recently admitted class of graduate students at a large state university has a mean GRE verbal score of 650 with a standard de
hjlf

Answer:

The answer is below

Step-by-step explanation:

The z score is a score used to determine the number of standard deviations by which the raw score is above or below the mean, it is given by the equation:

z=\frac{x-\mu}{\sigma} \\\\\mu=mean, \sigma=standard\ deviation,x=raw\ score\\\\for\ a\ sample\ n:\\\\z=\frac{x-\mu}{\sigma/\sqrt{n} }

Given that μ = 650, σ = 50. To find the probability that 5 students who have a mean of 490, we use:

z=\frac{x-\mu}{\sigma/\sqrt{n} } =\frac{490-650}{50/\sqrt{5} } =-7.16

From the normal distribution table, P(x < 490) = P(Z < -7.16) = 0.0001 = 0.01%

Since only a small percentage of people score about 490, hence the local newspaper editor should write a scathing editorial about favoritism

4 0
3 years ago
Heya!
nataly862011 [7]

Answer:

m\angle QSN=65^\circ

Step-by-step explanation:

In the given figure, PQRS is a rhombus and SRM is an equilateral triangle.

We are also given that SN⊥RM and that ∠PRS = 55°.

And we want to find the measure of ∠QSN.

Remember that since PQRS is a rhombus, the angles formed by its diagonals are right angles. Let the intersection point of the diagonals be K. Therefore:

m\angle RKS=90^\circ

Now, RKS is also a triangle. The interior angles of all triangles must be 180. Thus:

m\angle RKS+m\angle KSR+m\angle SRK=180

Substitute in known values:

90+55+m\angle KSR=180

Solve for ∠KSR:

m\angle KSR+145=180\Rightarrow m\angle KSR=35^\circ

Since SRM is an equilateral triangle, this means that:

m\angle SRM=m\angle RMS=m\angle MSR=60^\circ

Note that RNS is also a triangle. Therefore:

m\angle SRM+m\angle RNS+m\angle NSR=180

Substitute in known values:

60+90+m\angle NSR=180

So:

m\angle NSR+150=180\Rightarrow m\angle NSR=30^\circ

∠QSN is the addition of the two angles:

m\angle QSN=m\angle KSR+m\angle NSR

Therefore:

m\angle QSN=35+30=65^\circ

4 0
3 years ago
Read 2 more answers
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Vikentia [17]

Answer:

3x^2 + 3  -->  6, 15, 30, 51

2x^2 - 1    -->  1, 7, 17, 31

x^2 + 2     -->  3, 6, 11, 18

Step-by-step explanation:

Let's start with the first equation; 3x^2 + 3

Substitute 1 (the first digit in a sequence) for x.

3(1^2) + 3

3(1) + 3

3 + 3 = <u>6</u>

3(2^2) + 3 Then the second digit.

3(4) + 3

12 + 3 = <u>15</u>

Since the two numbers we have so far are 6 and 15, there is only one sequence this could match. 6, 15, 30, 51.

2(1^2) - 1

2(1) - 1

2 - 1 = <u>1</u>

This equation represents 1, 7, 17, 31.

These same steps apply to the other equation as well.

1^2 + 2, then 2^2 + 2, then 2^2 + 2, and so on. (But we don't need to do extra work to figure that out.)

7 0
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A box of cereal states that there are 87 calories in a 3​-4cup serving. What is the unit rate for calories per​ cup? How many ca
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Answer: for 2 cups, There are 232 Calories.

Step-by-step explanation:

Step 1

Let the calories in one cup be represented as C

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3/4 x C = 87 calories

C = 87 X 4 / 3 = 116

unit rate is 116 calories per cup.

Step 2- Solving the number of calories in 2 cups

1 cup serving = 116 calories

2 cups servings = 116 x 2= 232 calories

3 0
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