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3 years ago

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Scores on an exam are normally distributed with a mean of 67.5 and a standard deviation of 10. Find the percent of the scores th

at satisfy each question.
a)Less than 32

b)At least 70

c)Between 56 and 66

1 answer:

lozanna [386]3 years ago

6 0

Answer:

C

Step-by-step explanation:

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If BI=9 and HA=15, find the scale factor

inessss [21]

Answer:

5:3

Step-by-step explanation:

to find the scale factor you set up the proportion as 15/9 and reduce to 5/3

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3 years ago

Expand 4x(7x-11)<br> For maths <br> Help please

harina [27]

Answer:

$28x^2-44x$

Step-by-step explanation:

Use the distributive property.

$4x * 7x = 28x^2$

$4x * (-11) = -44x$

We will get $28x^2-44x$

Hope this helps!

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3 years ago

May have to flip or look closely in order to see the question. Brainliest involved

Gwar [14]

Answer:

The answer is step 5

Step-by-step explanation:

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3 years ago

Use the functions f(x) = 4x − 5 and g(x) = 3x + 9 to complete the function operations listed below.

JulijaS [17]

A:

(f+g)(x)=f(x)+g(x)

(f+g)(x)=4x-5+3x+9

(f+g)(x)=7x+4

B:

(f•g)(x)=f(x)•g(x)

(f•g)(x)=(4x-5)(3x+9)

(f•g)(x)=12x^2-15x+36x-45

(f•g)(x)=12x^2+21x-45

C:

(f○g)(x)=f(g(x))

(f○g)(x)=4(3x+9)-5

(f○g)(x)=12x+36-5

(f○g)(x)=12x+31

6 0

3 years ago

Assume that the following data were generated using a valid and appropriate methodology. XYZ Data Analytics, Inc. Received prope

Hitman42 [59]

Using the z-distribution, as we are working with a proportion, the 95% confidence interval for the proportion of consumers who would buy the product at it's proposed price is (0.3016, 0.3830).

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which:

$\pi$ is the sample proportion.

z is the critical value.

n is the sample size.

In this problem, we have a 95% confidence level, hence $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so the critical value is z = 1.96.

179 out of 523 members indicated they would buy the new product at the proposed price, hence:

$\pi = \frac{179}{523} = 0.3423$

Then the bounds of the interval are found as follows:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.3423 - 1.96\sqrt{\frac{0.3423(0.6577)}{523}} = 0.3016$

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.3423 + 1.96\sqrt{\frac{0.3423(0.6577)}{523}} = 0.3830$

More can be learned about the z-distribution at brainly.com/question/25890103

4 0

2 years ago