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3 years ago

-3/5x - 7/20x + 1/4x= -56

Mathematics

2 answers:

romanna [79]3 years ago

8 0

Answer:

x = 80

Step-by-step explanation:

Combine − 3/5x and 7/20x to get -19/20x.

Then combine -19/20x and 1/4x and you get -7/10x.

Then you multiply both sides by -10/7 which is the reciprocal of -7/10.

Make -56(-10) one fraction.

Multiply -56 and -10 and you get 560.

Then divide 560 by 7 to get 80.

Ira Lisetskai [31]3 years ago

5 0

80 I think but I’m not sure

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A restaurant serves custom-made omelets, where guests select meat, cheese, and vegetables to be added to their omelet. There are

FrozenT [24]

Answer:

15 possible combinations

Step-by-step explanation:

Given

$Vegetables = 6$

$Selection = 2$

Required

Determine the possible number of combinations

The question emphasizes on "selection" which means "combination".

So; To answer this question, we apply the following combination formula:

$^nC_r = \frac{n!}{(n-r)r!}$

In this case:

$n = 6$

$r = 2$

The formula becomes:

$^6C_2 = \frac{6!}{(6-2)!2!}$

$^6C_2 = \frac{6!}{4!2!}$

$^6C_2 = \frac{6*5*4!}{4!2*1}$

$^6C_2 = \frac{6*5}{2}$

$^6C_2 = \frac{30}{2}$

$^6C_2 = 15$

<em>Hence, there are 15 possible combinations</em>

7 0

3 years ago

Niko uses 12 marshmallows and 8 graham crackers to make 4 s'mores.

Lerok [7]

Answer:

6 crackers, 9 marshmallows

Step-by-step explanation:

You have to divide to find how many graham crackers and marshmallows are needed to make 1 s'more:

8 / 4 = 2, so 2 crackers per s'more. Then,

12 / 4 = 3, so 3 marshmallows per s'more. Now that we know this, all we have to do is multiply each number by 3 to make 3 s'mores.

2 * 3 = 6, so 6 crackers, and

3 * 3 = 9, so 9 marshmallows.

3 0

3 years ago

Read 2 more answers

The drama club sold bags of candy and cookies to raise money for the spring show. Bags of candy cost $8.00, and bags of cookies

vodka [1.7K]

Answer:

Number of bags of candy = 2

Number of bags of cookies = 7

Step-by-step explanation:

Let, number of bags of candy = X

So, Number of bags of cookies = X + 5

Cost of candy bag = $8

Cost of cookies bag = $2.5

Total sales = $33.50

So, Total cost of Candy Bags + Total cost of cookies bags = Total sales

= 8X + 2.5 ( X +5) = 33.50

= 8X + 2.5X + 12.5 = 33.50

= 10.5X = 33.50 - 12.5

= 10.5X = 21

X = 2

So, number of bags of candy = 2

Number of bags of cookies = 2 + 5 = 7

4 0

3 years ago

An algebra book weighs 6 oz less

Mashcka [7]

Answer:

Algebra book weighs 24 oz

Grammar book weighs 15 oz

Step-by-step explanation:

algebra = x and grammar = y

x = 2y-6

5x = 8y

5(2y-6) = 8y

10y - 30 = 8y

2y - 30 = 0

2y = 30

y = 15

x = 2(15)-6

x = 30-6

x = 24

8 0

3 years ago

During a tournament, a batting cage can be used for $5.00 for 50 pitches. If all 192 players use the cage one time, how much mon

Fynjy0 [20]

First, we have to find the rate:
500/50
100/10
10/1
10 cents a pitch:
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It will cost $12.90

7 0

3 years ago