Answer: There are 1.52 pints in 720 mililiters.
Step-by-step explanation:
You need to remember that there are 473.176 mililiters in 1 pint.
Therefore, having 720 mililiters, you need to make the corresponding conversion from mililiters to pints.
Then, you get that 720 mililiters to pints is:

Therefore, the answers is: There are 1.52 pints in 720 mililiters.
Answer: $889.58
Step-by-step explanation:
⇒<u>Equation:</u>
A = P(1 + rt)
Turn 3% into decimal and you get 0.03, then 9 months/ 12 months = 0.75 years.
<h2><u>
WORK ↓</u></h2>
⇒A = 870(1 + (0.03 × 0.75)) = 889.575
⇒A = $889.58
* Hopefully this helps:) Mark me the brainliest:) !!!!
Answer:
95% Confidence interval for the mean

Step-by-step explanation:
We have to calculate a 95% confidence interval for the mean of a finite population.
The error is multiplied by the following finite population correction factor:

The standard deviation can be estimated as

The 95% confidence interval has a z value of 1.96, so it becomes:

I=prt,,5.00=.0125*1212p,,p=5.00/.0125*1212=?? Use the calculator
1. The growth rate equation has a general form of:
y = A (r)^t
The function is growth when r≥1, and it is a decay when
r<1. Therefore:
y=200(0.5)^2t -->
Decay
y=1/2(2.5)^t/6 -->
Growth
y=(0.65)^t/4 -->
Decay
2. We rewrite the given equation (1/3)^d−5 = 81
Take the log of both sides:
(d – 5) log(1/3) = log 81
d – 5 = log 81 / log(1/3)
d – 5 = - 4
Multiply both sides by negative 1:
- d + 5 = 4
So the answer is D