Find the slope of the line containing the points in the table below

Mathematics

1 answer:

zhannawk [14.2K]3 years ago

6 0

Answer:

slope = 3

Step-by-step explanation:

Choose any two points: For example, (2, 4) and (4, 10)

Find the difference in y. This is called the "rise."

rise = 10 - 4 = 6

In the same order, find the difference in x. this is called the "run."

run = 4 - 2 = 2

slope = rise/run

slope = 6/2

slope = 3

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Segment AB has point A located at (6, 5). If the distance from A to B is 5 units, which of the following could be used to calcul

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The expression $5 = \sqrt{(x-6^2)+(y - 5)^2}$ can be used to find the coordinate of Point B. Option C is correct.

Given that,
Segment AB has point A located at (6, 5). If the distance from A to B is 5 units, which of the following could be used to calculate the coordinates for point B is to be determined.

<h3>What is the equation?</h3>

The equation is the relationship between variables and represented as y = ax +c is an example of a polynomial equation.

Let the coordinates of B be (x, y)
Now the distance between A (6, 5) and B (x, y) is c = 5 units
So, by the distance formula, the distance between two points is given as,

$C = \sqrt{(x_1-x_2)^2 +(y_1-y_2)^2}$

now put the value in the formula.

$5 = \sqrt{(x-6^2)+(y - 5)^2}$

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1 year ago

Solve the following equation by completing the square. 3x^2-3x-5=13

mr Goodwill [35]

we'll start off by grouping some

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so we have a missing guy at the end in order to get the a perfect square trinomial from that group, hmmm, what is it anyway?

well, let's recall that a perfect square trinomial is

$\bf \qquad \textit{perfect square trinomial} \\\\ (a\pm b)^2\implies a^2\pm \stackrel{\stackrel{\text{\small 2}\cdot \sqrt{\textit{\small a}^2}\cdot \sqrt{\textit{\small b}^2}}{\downarrow }}{2ab} + b^2$

so we know that the middle term in the trinomial, is really 2 times the other two without the exponent, well, in our case, the middle term is just "x", well is really -x, but we'll add the minus later, we only use the positive coefficient and variable, so we'll use "x" to find the last term.

$\bf \stackrel{\textit{middle term}}{2(x)(?)}=\stackrel{\textit{middle term}}{x}\implies ?=\cfrac{x}{2x}\implies ?=\cfrac{1}{2}$

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