Answer:
B 1
Step-by-step explanation:
Since the divisor is in the form of <em>x - c</em>, use what is called Synthetic Division. Remember, in this formula, -c gives you the OPPOSITE terms of what they really are, so do not forget it. Anyway, here is how it is done:
2| -2 1 5 0 4 1
↓ -4 -6 -2 -4 0
_________________
-2 -3 -1 -2 0 1→ -2x⁴ - 3x³ - x² -2x + [x - 2]⁻¹
You start by placing the <em>c</em> in the top left corner, then list all the coefficients of your dividend [-2x⁵ + x⁴ + 5x³ + 4x + 1]. You bring down the original term closest to <em>c</em> then begin your multiplication. Now depending on what symbol your result is, tells you whether the next step is to <em>subtract</em> or <em>add</em>, then you continue this process starting with multiplication all the way up until you reach the end. Now, when the last term is 0, that means you have no remainder. Finally, your quotient is one degree less than your dividend, so that -2 in your quotient can be a -2x⁴, and the -3 [x³] follows right behind it, then 1 [-x²], -2[x], and finally, [1\x - 2] (remainder is 1, so set it over your denominator, which is the divisor), giving you the other factor of -2x⁴ - 3x³ - x² -2x + [x - 2]⁻¹.
I am joyous to assist you anytime.
**
Answer:
the answer is 20. 10+4+6 is 20
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
The red graph is a horizontal translation of 5 units left followed by a reflection in the x- axis.
Given f(x) then f(x + a) is a horizontal translation of f(x)
• If a > 0 then a shift to the left of a units
• If a < 0 then a shift to the right of a units
The black graph is shifted 5 units left, thus
f(x) → f(x + 5)
Under a reflection in the x- axis
a point (x, y ) → (x, - y )
Note that the y- coordinate of the image is the negative of the original
Note also that
= - y, thus
= f(x + 5) → B
Answer:
14
Step-by-step explanation:
Hope this will help you....
Answer:
Step-by-step explanation:
Their point of intersection, assuming there is one, will be somewhere on the line y = x. This line, y = x, is the line of symmetry between a function and its inverse. So if the two do in fact intersect, it will be at some point on that line