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3 years ago

Chemistry in formula of water

Chemistry

2 answers:

Keith_Richards [23]3 years ago

4 0

Answer: Unbalanced : H2O

Balanced : 2H2O

Explanation:

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katovenus [111]3 years ago

4 0

H2O

Explanation:

Water (chemical formula: H2O) is a transparent fluid which forms the world's streams, lakes, oceans and rain, and is the major constituent of the fluids of organisms. As a chemical compound, a water molecule contains one oxygen and two hydrogen atoms that are connected by covalent bonds.

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The molecular mass of propane-1,2-diol is 76.1 amuamu . Calculate the molecular mass of propane-1,3-diol, an isomer of propane-1

sashaice [31]

Answer:

76.1 amu

Explanation:

Let us recall that isomers refer to two different compounds with the same molecular formula but different atom to atom connectivity and different chemical properties. When two compounds are isomers, we can essentially represent them with exactly the same molecular formula.

Now propane-1,2-diol and propane-1,3-diol are both represented by the molecular formula C3H8O2 since they are isomers of each other. When two compounds have the same molecular formula, they must essentially have the same molecular mass. Hence the molecular mass of propane-1,3-diol is also 76.1 amu.

8 0

4 years ago

Read 2 more answers

A bond where electrons are transferred from a cation to an anion is called a (n) ___________bond.\

emmasim [6.3K]

When elements transfer electrons from a cation and an anion it called ionic bond.

6 0

4 years ago

What kind of non-flowering plant produces seeds instead of spores?

Pie

Answer:

The answer to your question is Ferns

Explanation:

Ferns are called nonflowering plants and produce spores instead of seeds.

6 0

3 years ago

What is the molarity of 2.00 L of a solution that contains 14.6 g NaCl?

White raven [17]

Answer: The molarity of the solution is 0.125 M

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

$Molarity=\frac{n}{V_s}$

where,

n = moles of solute

$V_s$ = volume of solution in L

moles of $NaCl$ = $\frac{\text {given mass}}{\text {Molar mass}}=\frac{14.6g}{58.5g/mol}=0.250mol$

Now put all the given values in the formula of molality, we get

$Molarity=\frac{0.250mol}{2.00L}=0.125M$

Therefore, the molarity of the solution is 0.125 M

8 0

3 years ago

A 1.00 g sample of octane (C8H18) is burned in a bomb calorimeter with a heat capacity of 837J∘C that holds 1200. g of water at

lubasha [3.4K]

Answer:

The heat of combustion for 1.00 mol of octane is -5485.7 kJ/mol

Explanation:

Step 1: Data given

Mass of octane = 1.00 grams

Heat capacity of calorimeter = 837 J/°C

Mass of water = 1200 grams

Temperature of water = 25.0°C

Final temperature : 33.2 °C

Step 2: Calculate heat absorbed by the calorimeter

q = c*ΔT

⇒ with c = the heat capacity of the calorimeter = 837 J/°C

⇒ with ΔT = The change of temperature = T2 - T1 = 33.2 - 25.0 : 8.2 °C

q = 837 * 8.2 = 6863.4 J

Step 3: Calculate heat absorbed by the water

q = m*c*ΔT

⇒ m = the mass of the water = 1200 grams

⇒ c = the specific heat of water = 4.184 J/g°C

⇒ ΔT = The change in temperature = T2 - T1 = 33.2 - 25 = 8.2 °C

q = 1200 * 4.184 * 8.2 = 41170.56 J

Step 4: Calculate the total heat

qcalorimeter + qwater = 6863.4 + 41170. 56 = 48033.96 J = 48 kJ

Since this is an exothermic reaction, there is heat released. q is positive but ΔH is negative.

Step 5: Calculate moles of octane

Moles octane = 1.00 gram / 114.23 g/mol

Moles octane = 0.00875 moles

Step 6: Calculate heat combustion for 1.00 mol of octane

ΔH = -48 kJ / 0.00875 moles

ΔH = -5485.7 kJ/mol

The heat of combustion for 1.00 mol of octane is -5485.7 kJ/mol

8 0

3 years ago

Chemistry in formula of water ​

Chemistry in formula of water