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mars1129 [50]
3 years ago
6

2NO(g) N2(g) + O2(g); Keq = 2.1 × 1030 What does the value of the equilibrium constant indicate?

Chemistry
1 answer:
olga_2 [115]3 years ago
7 0
The equilibrium constant is a value which represents the equilibrium of a reaction. It is a reaction quotient when the reaction reached equilibrium. If Keq is greater than 1, the mixture contains mostly the products. On the other hand, if Keq is less than 1, the mixture contains the reactants. For this case, the mixture contains mostly products.
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Nastasia [14]

Explanation:

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7 0
2 years ago
If a gas’s [kelvin] temperature doubles and it’s volume then remains the same, then what happens to it’s pressure?
Tamiku [17]

Answer:

The final pressure will double i.e it will be twice the initial pressure

Explanation:

T1 = T

T2 = 2T ( twice the original T)

P1 = P

P2 =?

Since the volume is constant,

P1/ T1 = P2 /T2

P/ T = P2 / 2T

Cross multiply

T x P2 = 2T x P

Divide both side by T

P2 = (2T x P) / T

P2 = 2P

Therefore, the final pressure will double i.e it will be twice the initial pressure

5 0
3 years ago
What is the most likely way a chemist would be involved in the production of<br> a computer chip?
ZanzabumX [31]

Answer: Computer chips are very complex, maybe there are things insode that chemists are familiar with. Maybe they can give insight about this.

Explanation:

4 0
3 years ago
Solid Al(NO3)3 is added to distilled water to produce a solution in which the concentration on nitrate, [NO3^-], is 0.10 M. What
VikaD [51]

Answer:

The concentration of nitrate ion NO_{3}^{-}  is 0.033 M.

Explanation:

Al(NO_{3})_{3} \rightarrow Al^{3+} + NO_{3}^{-}

1 mole of [Al^{3+}]  = 3 mole NO_{3}^{-}

Let  [NO_{3}^{-}]  = 3y

then according to above reaction,

[Al^{3+}] = y

[NO_{3}^{-}] = 0.10 M (given)

[Al^{3+}] = ?

3y = 0.10 M

y = \frac{0.1}{3}

y = 0.033 M

So ,concentration of [Al^{3+}] = y = 0.033 M

5 0
3 years ago
Why should you pay attention to the physical states of reactants and products when writing elquilibrium constant expressions?
babunello [35]
Answer is: because pure liquids (<span>shown in </span>chemical reactions<span> by appending (</span>l)<span> to the </span>chemical formula) and solids (<span>shown in </span>chemical equations by appending (s)<span> to the </span>chemical formula) not go in to he equilibrium constant expression, only gas state (shown in chemical reactions by appending (g) to the chemical formula) reactants and products go in to he equilibrium constant expression.
For example, equilibrium constant expression Kp for reaction:
A(s) + 2B(s) ⇄ 4C(g) + D(g).<span>
will be: Kp = [C]</span>⁴<span>·[D].
But for reaction </span>A(g) + 2B(g) ⇄ 4C(g) + D(g), will be:<span>
Kp = [C]</span>⁴<span>·[D] / [A]·[B]².</span>
3 0
4 years ago
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