Al + Br2 → AlBr3 To balance the Br’s, make 3 Br2 and 2 AlBr3. Al + 3 Br2 → 2 AlBr3
To balance the equation, make 2 Al.
2 Al + 3 Br2 → 2 AlBr3 ...... if you would like more information please let me know and I can help you out
You take the temperature and follow these steps:
Take the temperature in farenheit, suntract 32, then multiply that by 5, and divide by 9.
Answer : The concentration of
ion is 0.0375 M.
Explanation :
The balanced equilibrium reaction will be:

The expression for solubility constant for this reaction will be,
![K_{sp}=[Pb^{2+}][Cl^-]^2](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BPb%5E%7B2%2B%7D%5D%5BCl%5E-%5D%5E2)
Now put all the given values in this expression, we get:
![2.40\times 10^{-4}=[Pb^{2+}]\times (0.0800)^2](https://tex.z-dn.net/?f=2.40%5Ctimes%2010%5E%7B-4%7D%3D%5BPb%5E%7B2%2B%7D%5D%5Ctimes%20%280.0800%29%5E2)
![[Pb^{2+}]=0.0375M](https://tex.z-dn.net/?f=%5BPb%5E%7B2%2B%7D%5D%3D0.0375M)
Therefore, the concentration of
ion is 0.0375 M.