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kipiarov [429]
2 years ago
11

Marking brainliest Please help

Mathematics
1 answer:
Katen [24]2 years ago
6 0
The answer is lad missed lady plz brainliest
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(n+1)^3-n^3=1+3 (n+1)n using this formulae find the cube of 999.If cube of 1000 is 1000000000.
Nastasia [14]

We use the formula: ( a - b )^3 = a^3 - b^3 - 3ab( a - b);

a = 1000; b = 1;

999^3 = 1000^3 - 1^3 - 3·1000·1( 1000 - 1 ) = 1000000000 - 1 - 3000·999 = 1000000000 - 1 - 2997000 = 997002999;

6 0
3 years ago
This prism has a surface area of 172 cm². What would the surface of the prism be if each dimension was tripled? ( Scale factor i
Alex787 [66]

Answer:

1356 cm²

Step-by-step explanation:

Each dimension gets multiplied by 2, so the new dimensions are

changed from 2x8x7 to 6x24x21

There are 6 faces to the prism,

The area of the front and back are 6x21 = 126.  There are 2 of them for a total area of 126x2 = 252 cm²

The are of the left and right sides are 24x21 = 504.  There are 2 of them for a total area of 504x2 = 1008 cm²

The area of the top and bottom are 6x24 = 144, there are 2 of them for a total area of 144x2 = 288 cm²

The total surface area is 252 + 1008 + 96 = 1356 cm²

7 0
3 years ago
What % of 400 = 193
kondor19780726 [428]
(193/400 )x100 equals 48.25 %
8 0
3 years ago
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Solve for x using the quadratic formula. 4x^2-3x+8=0
Paraphin [41]

Answer:

answer : x = 3±√ 119 / 16

is correct answer ...plz mark my answer as brainlist ... plzzzz and plz vote me as brainlist

8 0
3 years ago
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(5x^3-8x^2+9x+12)/(x-3)<br><br> please answer with sentences on how to do it step by step. thanks!
Anastaziya [24]

Answer:

5x^2+7x+30+\frac{102}{x-3}

Step-by-step explanation:

\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}5x^3-8x^2+9x+12\\\mathrm{and\:the\:divisor\:}x-3\mathrm{\::\:}\frac{5x^3}{x}=5x^2\\\mathrm{Quotient}=5x^2\\\mathrm{Multiply\:}x-3\mathrm{\:by\:}5x^2:\:5x^3-15x^2\\\mathrm{Subtract\:}5x^3-15x^2\mathrm{\:from\:}5x^3-8x^2+9x+12\mathrm{\:to\:get\:new\:remainder}\\\mathrm{Remainder}=7x^2+9x+12\\\mathrm{Therefore}\\=5x^2+\frac{7x^2+9x+12}{x-3}

\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}7x^2+9x+12\\\mathrm{and\:the\:divisor\:}x-3\mathrm{\::\:}\frac{7x^2}{x}=7x\\\mathrm{Quotient}=7x\\\mathrm{Multiply\:}x-3\mathrm{\:by\:}7x:\:7x^2-21x\\\mathrm{Subtract\:}7x^2-21x\mathrm{\:from\:}7x^2+9x+12\mathrm{\:to\:get\:new\:remainder}\\\mathrm{Remainder}=30x+12\\\mathrm{Therefore}\\=5x^2+7x+\frac{30x+12}{x-3}\\

\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}30x+12\\\mathrm{and\:the\:divisor\:}x-3\mathrm{\::\:}\frac{30x}{x}=30\\\mathrm{Quotient}=30\\\mathrm{Multiply\:}x-3\mathrm{\:by\:}30:\:30x-90\\\mathrm{Subtract\:}30x-90\mathrm{\:from\:}30x+12\mathrm{\:to\:get\:new\:remainder}\\\mathrm{Remainder}=102\\\mathrm{Therefore}\\=5x^2+7x+30+\frac{102}{x-3}

6 0
2 years ago
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