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Over [174]
3 years ago
15

Which formula can be used to describe the sequence? , −4, −24, −144,... f(x) = 6 f(x) = −6 f(x) = (6)x − 1 f(x) = (−6)x − 1

Mathematics
2 answers:
Elanso [62]3 years ago
8 0

Answer:

c

Step-by-step explanation:

WITCHER [35]3 years ago
5 0

Answer:

The general formula that represents the given sequence is:

f(x)=-\dfrac{2}{3}\times 6^x

Step-by-step explanation:

We are given a sequence as:

−4, −24, −144,...

The first term is:

-4.

second term is:

-24 and so on.

So, looking at the sequence the general formula that can be formed is:

f(x)=-\dfrac{2}{3}\times 6^x

Hence, the first term i..e when x=1 we have:

f(1)=-\dfrac{2}{3}\times 6\\\\f(1)=-2\times 2\\\\f(1)=-4

Similarly the second term i.e. when x=2 we have:

f(2)=-\dfrac{2}{3}\times 6^2\\\\f(2)=-24

and so on.

Hence, the general formula is:

f(x)=-\dfrac{2}{3}\times 6^x

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Given that sectheta = -37/12 what is the value of cottheta for pi/2 &lt; theta&lt; pi?
lys-0071 [83]

Answer:

cotg(\theta) = -\frac{12}{35}

Step-by-step explanation:

The cotangent of theta is:

cotg(\theta) = \frac{\cos{\theta}}{\sin{\theta}}

For pi/2 < theta< pi

This means that the angle is in the second quadrant. In the second quadrant, the cosine is negative and the sine is positive. This means that the cotangent will be negative.

Secant:

sec(\theta) = \frac{1}{\cos{\theta}}

In this question

sec(\theta) = -\frac{37}{12}

So

-\frac{37}{12} = \frac{1}{\cos{\theta}}

Using cross multiplication

-37\cos{\theta} = 12

37\cos{\theta} = -12

\cos{\theta} = -\frac{12}{37}

Now we apply the following trigonometric identity:

\sin{\theta}^{2} + \cos{\theta}^{2} = 1

\sin{\theta}^{2} + (-\frac{12}{37})^{2} = 1

\sin{\theta}^{2} = 1 - (-\frac{12}{37})^{2}

\sin{\theta}^{2} = 1 - \frac{144}{1369}

\sin{\theta}^{2} = \frac{1369 - 144}{1369}

\sin{\theta} = \pm \sqrt{\frac{1225}{1369}}

Since the angle is in the second quadrant, the sine is positive.

\sin{\theta} = \frac{35}{37}

Finally, the cotangent:

cotg(\theta) = \frac{\cos{\theta}}{\sin{\theta}}

cotg(\theta) = \frac{-\frac{12}{37}}{\frac{35}{37}}

cotg(\theta) = -\frac{12}{35}

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4 years ago
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