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3 years ago

A+6,when a=2? Pls answer

Mathematics

1 answer:

vlabodo [156]3 years ago

5 0

Answer:

Step-by-step explanation:

a + 6; a = 2

2 + 6 = 8

Thus, The answer is 8

-TheUnknownScientist

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3a <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B3a%20%2B%20a%20%7B%7D%5E%7B2%7D%20%7D%7Ba%7D%20" id="TexFormula1" title="

egoroff_w [7]

Answer:

(3+a)

Step-by-step explanation:

3a + a^2

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Factor out an a in the numerator

a(3+a)

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Cancel like terms

(3+a)

6 0

2 years ago

Read 2 more answers

5. Mrs.Weed's puppy weighed o.236 kg when it was born. At the next check-up it weighed 0.37 kg. How much weight had it gained?

musickatia [10]

Answer:

5.) 0.134 kg.

6.) 6.15 km.

7.) 5.9 kg.

Step-by-step explanation:

5.) 0.37 - 0.236 = 0.134

6.) 9.71 - 3.56 = 6.15

7.) 1.7 + 4.2 = 5.9

5 0

3 years ago

Lim x--> 0 (e^x(sinx)(tax))/x^2

Tom [10]

Make use of the known limit,

$\displaystyle\lim_{x\to0}\frac{\sin x}x=1$

We have

$\displaystyle\lim_{x\to0}\frac{e^x\sin x\tan x}{x^2}=\left(\lim_{x\to0}\frac{e^x}{\cos x}\right)\left(\lim_{x\to0}\frac{\sin^2x}{x^2}\right)$

since $\tan x=\dfrac{\sin x}{\cos x}$ , and the limit of a product is the same as the product of limits.

$\dfrac{e^x}{\cos x}$ is continuous at $x=0$ , and $\dfrac{e^0}{\cos 0}=1$ . The remaining limit is also 1, since

$\displaystyle\lim_{x\to0}\frac{\sin^2x}{x^2}=\left(\lim_{x\to0}\frac{\sin x}x\right)^2=1^2=1$

so the overall limit is 1.

4 0

3 years ago

Write an inequality for the following statement. c is less than or equal to 5

tresset_1 [31]

Answer:

c ≤5

Step-by-step explanation:

less than or equal is ≤

c ≤5

3 0

2 years ago

Read 2 more answers

Select the correct answer.

Butoxors [25]

Answer:

Approximately 163 seconds (A)

Step-by-step explanation:

Line up 192 months on the x-axis with the line of best fit then run it across to the y-axis and it should be around 163 seconds.

8 0

3 years ago