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3 years ago

Which expression is equivalent to 4a+4/2a * a^2/a+1

Mathematics

2 answers:

gregori [183]3 years ago

8 0

Answer:

its C on edge

Step-by-step explanation:

Viktor [21]3 years ago

5 0

((4a+4)/(2a))((a^2)/(a+1))
(2(2a+2)/2(a))((a^2)/(a+1))
((2a+2)(a^2))/(a(a+1))
(2(a+1)(a^2))/(a(a+1))
(2a^2)/a
=2a

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Answer:

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3 years ago

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3 years ago

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igor_vitrenko [27]

Answer:

1st Question:

(2,-3)

(3,-1)

(3,1)

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(5,3)

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y=-2+10x (graph in desmos to be sure)

Step-by-step explanation:

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3 0

3 years ago

1. Two object accumulated a charge of

In-s [12.5K]

Answer:

The magnitude of the electric force between these two objects

will be: 181.274 N.

i.e. F $=181.274$ N

Step-by-step explanation:

Two object accumulated a charge of 4.5 μC and another a charge of 2.8 μC.

q₁ = 4.5 μC = 4.5 × 10⁻⁶ C

q₂ = 2.8 μC = 2.8 × 10⁻⁶ C

separated distance = d = 2.5 cm

Calculating the magnitude of the force between two charged objects using the formula:

$F = \frac{1}{4\pi \epsilon_0}\frac{q_1 q_2}{r^2}$

$=\:\frac{4.5\times \:\:10^{-6}\:\times \:\:2.8\:\times \:\:10^{-6}}{4\:\times \:\left(3.14\right)\:\times \:\left(8.85\times \:10^{-12}\right)\times \left(2.5\times \:\:10^{-2}\right)^2}$

$=\frac{10^{-12}\times \:12.6}{10^{-12}\times \:4\times \:8.85\pi \left(10^{-2}\times \:2.5\right)^2}$ ∵ $4.5\times \:10^{-6}\times \:2.8\times \:10^{-6}=10^{-12}\times \:12.6$

$=\frac{10^{-12}\times \:12.6}{10^{-12}\times \:35.4\pi \left(10^{-2}\times \:2.5\right)^2}$ ∵ $\mathrm{Multiply\:the\:numbers:}\:4\times \:8.85=35.4$