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liberstina [14]
3 years ago
11

HELPPPPPPPPPPPPPPPPPPPPPPPPPEPPPPPPPPPPPPPPPPPPPPPPP

Mathematics
1 answer:
igor_vitrenko [27]3 years ago
3 0

Answer:

1st Question:

(2,-3)

(3,-1)

(3,1)

(4,1)

(5,3)

2nd Question

y=-2+10x (graph in desmos to be sure)

Step-by-step explanation:

1st Question: just write the x and the y that the x is pointing to

2nd Question: type the points on a table in desmos and find a equation that goes through the same line

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2 less than one-third of the points that the Panthers scored. How do you write this as an algebraic expression.
Diano4ka-milaya [45]

Answer: \frac{x}{3} -2

Step-by-step explanation:

Let panther scores x points.

Therefore, one-third of the points that the Panthers scored = \frac{x}{3}

Thus, 2 less than one-third of the points that the Panthers scored = one-third of the points that the Panthers scored-2 = \frac{x}{3} -2

Which is the required algebraic expression.


3 0
3 years ago
I KINDA NEED HELP WITH THIS ILL GIVE BRAINLIST WHOEVER HAS THE CORRECT ANSWER! THANKS
Drupady [299]

Answer: 48

Step-by-step explanation: YOU MULTIPLY 6 AND 8.

6 0
3 years ago
Read 2 more answers
Find the range median first and third interquartile range for each data set
liraira [26]

Answer:

Range = 1.8

Median = 6.3

First Quartile = 6.3

Thrid Quartile = 6.8

Interquartile Range =  0.5

Step-by-step explanation:

First we need to arrange the data set from lowest to highest.

4.9, 5.8, 6.1, 6.2, 6.3, 6.3, 6.4, 6.6, 6.7, 6.7

To find the range of the data set, we simply take the highest value and subtract it to the lowest value.

Range = 6.7 - 4.9

Range = 1.8

To find the Median we need to get the middle number of the range. In this case there are two numbers in the middle of the set.

So we get both of them and get their average.

Median = 6.3 + 6.3 /2

Median = 6.3

To get the first quartile, we simply get the median of the lower of the data set.

4.9, 5.8, 6.1, 6.2, 6.3

The median of the first quartile is 6.1.

To get the third quartile, we get the median of the upper half of the data set.

6.3, 6.4, 6.6, 6.7, 6.7

The median of the third quartile is 6.6

To get the interquartile range, we need to subtract the median of the third quartile to the median of the first quartile.

Interquartile Range = 6.6 - 6.1

Interquartile Range = 0.5

Answer:

Range = 32

Median = 17.5

First Quartile = 15

Thrid Quartile = 19

Interquartile Range =  4

Step-by-step explanation:

First we need to arrange the data set from lowest to highest.

4, 9, 15, 16, 17, 18, 18, 19, 19, 36

To find the range of the data set, we simply take the highest value and subtract it to the lowest value.

Range = 36 - 4

Range = 32

To find the Median we need to get the middle number of the range. In this case there are two numbers in the middle of the set.

So we get both of them and get their average.

Median = 17 + 18 /2

Median = 17.5

To get the first quartile, we simply get the median of the lower of the data set.

4, 9, 15, 16, 17,

The median of the first quartile is 15.

To get the third quartile, we get the median of the upper half of the data set.

18, 18, 19, 19, 36

The median of the third quartile is 19.

To get the interquartile range, we need to subtract the median of the third quartile to the median of the first quartile.

Interquartile Range = 19 - 15

Interquartile Range = 4

6 0
3 years ago
Read 2 more answers
You notice that on the days when you are off from school, you read more. What does this illustrate?
ddd [48]

Answer:

The answer is D. Correlation

Step-by-step explanation:

I had this on a test... tell me if Im wrong but I am not

3 0
3 years ago
(x^3-6x^2-9)/(x-6) long division
qaws [65]

Answer:

Step-by-step explanation:

=0

3 0
4 years ago
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