Question

ALGEBRA HELP, please help with problem, and show work

Answer 1

Divide both sides by 4x:
x^2-2x+1=0
You can either factor, complete the square, or use the quadratic formula.
I'll factor this into (x-1)(x-1)=0
x-1=0, so x=1

Answer 2

First of all, your second term is already wrong.  When you divided  8x²  by  4 ,
you should have written  2x² , not  4x² .

Make that correction, and then divide the whole thing by  'x'.

Then you'll have    x² - 2x + 1 = 0 .

You should have no trouble solving that one,
(especially since it's a perfect square)

That gives you two (equal) solutions.  But you should also ask yourself:
"Self !  Where is the third solution ?  A cubic equation like the original
one needs three solutions."

I'll give you that one:
Look over the original equation, and look at what happens to it when  x = 0 . 
Then the left side becomes zero, and the equation is  0 = 0 .  Since that's a
true statement, " x = 0 "  is another solution of the cubic equation, and now
you have all three of them.