Color change, temperature change, bubbling, state change
green to blue, hot to cold, bubbles (lol), and liquid to gas
Hi,
To solve the question, first of all we will find out the no. of moles of H2SO4 in 19 g of sulfuric acid.
As we know:
No . of moles = Mass/ Molar mass
No. of moles= 19 g/98.08
g
No. of moles= 0.1937
Now we know the no of moles of H2SO4 that will react with 2LiOH. We also know the molar equivalence of H2SO4 , and 2LiOH that will react.
So, the water that will be produced will be 2H2O and 1 Li2SO4 when H2SO4 that will react with 2LiOH.
0.1937 x 2x 18.01
=6.977
=6.98
Therefore, approximately 6.98 grams of water will be produced from 19 g of sulfuric acid.
Hope it helps!
Answer:
110V
Explanation:
Given parameters:
Current in the lightbulb = 0.5A
Resistance = 220Ω
Unknown:
Voltage = ?
Solution:
To solve this problem, we apply the equation derived from ohm's law;
V = IR
So,
V = 0.5 x 220 = 110V
The atomic number, the number of protons and the number of electrons.