The ratio of aluminum bronze components is:
92.0 Cu / 8.0 Al
The ratio of Cu and Al avilable is: 73.5 Cu / 42.2 Al
Then, it is evident that Al is in excess and Cu is the limitant material.
So, you need two work with the open proportion 92.0/ 8.0 = 73.5Cu / x
=> x = 73.5 * 8 / 92 = 6.39
Then, you can use 6.4 grams of Al and 73.5 grams of Cu to prepare 6.39g + 73.5g = 79.89.grams of Bronze.
I hope this helps.
1. 3 elements, Mg: 1, S: 1, O: 4
2. 3 elements, Li: 3, P: 1, O: 4
3. 3 elements, H: 2, S: 1, O: 4
1. KOH
2. AlOH
3. AlSO4
The identity of a metal that has a mass of 27.0g and a volume of 10.0cm is Aluminium. That is option B.
<h3>What is molar mass?</h3>
Molar mass is defined as the mass in grams of one mole of an element. This is measured in grams/mole of that substance.
The metal that is 27.0 g and a volume of 10.0 cm3 is aluminium because aluminium is 27 times heavier than 1/12th of the mass of carbon-12 atom.
Therefore, the identity of a metal that has a mass of 27.0g and a volume of 10.0cm is Aluminium.
Learn more about molar mass here:
brainly.com/question/837939
#SPJ1
Answer:
D. The sun's light helps plants grow
Explanation:
This is a scientific observation, because it is describing the structure of a living thing.
Answer:
(1) the surface area of the solute,
(2) the temperature of the solvent,
(3) the amount of agitation that occurs when the solute and the solvent are mixed.
Explanation:
