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lana [24]
3 years ago
10

How are point source and nonpoint source pollution harmful when it rains

Chemistry
1 answer:
kirza4 [7]3 years ago
4 0

Answer:

Nonpoint source pollution is difficult to control because it comes from many different sources and locations. Most nonpoint source pollution occurs as a result of runoff. When rain or melted snow moves over and through the ground, the water absorbs and assimilates any pollutants it comes into contact with.

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Save the ________ used to extract metals.
MrRa [10]

Answer:

Save the *minerals* used to extract metals.

6 0
2 years ago
Carbondioxide gas is't collectable in water. why​?
Lisa [10]

Answer:

carbon dioxide is a gas so it isn't collected over water.

Explanation:

it works for insoluble gases such as hydrogen,or gases that do not dissolve easily in water such as ammonia and chlorine are readily soluble in water and are not collected this way.

hope it is helpful for you.

4 0
3 years ago
What fraction can be used in conversion of 32 m3 to mm3
zimovet [89]
The calculation is (Measurement in m³ x 1000³)


Therefore

Measurement in m³ x 1 000 000

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5 0
3 years ago
Read 2 more answers
I NEED HELP I WILL RATE BRAINLIEST!!!
Mila [183]
I think it is True because the SI unit is <span>J/°C</span>
7 0
3 years ago
PLZ HELP ILL GIVE BRAINLIST!
Schach [20]

Answer:

The energy of a wave is inversely proportional to the wavelength of the wave.

As wavelength increases, the energy of the wave decreases.

As wavelength decreases, the energy of the wave increases.

Explanation:

The energy of a wave is directly proportional to the wave's frequency. As frequency increases, so does the energy of the wave.

E\propto f (energy E is proportional to frequency f)

<u>How is this related to wavelength?</u>

Frequency is inversely proportional to wavelength. That means that as frequency increases, wavelength decreases and as frequency decreases, wavelength increases.

f\propto \frac{1}{\lambda} (frequency f is inversely proportional to wavelength \lambda)

Therefore, as wavelength increases, the energy of a wave decreases and as wavelength decreases, the energy of a wave increases.

E\propto f\propto \frac{1}{\lambda}

6 0
3 years ago
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