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2 years ago

How are point source and nonpoint source pollution harmful when it rains

Chemistry

1 answer:

kirza4 [7]2 years ago

4 0

Answer:

Nonpoint source pollution is difficult to control because it comes from many different sources and locations. Most nonpoint source pollution occurs as a result of runoff. When rain or melted snow moves over and through the ground, the water absorbs and assimilates any pollutants it comes into contact with.

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I NEED HELP PLEASE, THANKS! :)

marin [14]

Answer:

$\large \boxed{1.447 \times 10^{23}\text{ molecules Cu(OH)}_{2 }}$

Explanation:

1. Calculate the moles of copper(II) hydroxide

$\text{Moles of Cu(OH)}_{2} = \text{23.45 g Cu(OH)}_{2} \times \dfrac{\text{1 mol Cu(OH)}_{2}}{\text{97.562 g Cu(OH)}_{2}} = \\\\\text{0.240 36 mol Cu(OH)}_{2}$

2. Calculate the molecules of copper(II) hydroxide

$\text{No. of molecules} = \text{0.240 36 mol Cu(OH)}_{2} \times \dfrac{6.022 \times 10^{23}\text{ molecules Cu(OH)}_{2}}{\text{1 mol Cu(OH)}_{2}}\\\\= 1.447 \times 10^{23}\text{ molecules Cu(OH)}_{2}\\\text{The sample contains $\large \boxed{\mathbf{1.447 \times 10^{23}}\textbf{ molecules Cu(OH)}_{\mathbf{2}}}$}$

6 0

3 years ago

Does beryllium (Be) or Sodium (Na) have the same electron arrangement as Magnesium (Mg)? Why?

Finger [1]

Answer:

Na has the most similar configuration.

Explanation:

Na electron configuration: 1s²2s²2p⁶3s¹ or [Ne] 3s₁

Mg electron configuration: 1s²2s²2p⁶3s² or [Ne] 3s²

Be electron configuration: 1s²2s² or [He] 2s²

This is because Na and Mg are right next to each other in the same period (horizontal).

3 0

3 years ago

What is the number of orbitals in an atom of radon

yan [13]

86 elections so 43 orbitals

6 0

3 years ago

What kind of change results in a new substance being produced

tatiyna

Chemical change creates a new substance

3 0

3 years ago

Read 2 more answers

Can anybody check my answer?

anzhelika [568]

Answer:

$\boxed{\text{25. 20 L; 26. 49 K}}$

Explanation:

25. Boyle's Law

The temperature and amount of gas are constant, so we can use Boyle’s Law.

$p_{1}V_{1} = p_{2}V_{2}$

Data:

$\begin{array}{rcrrcl}p_{1}& =& \text{100 kPa}\qquad & V_{1} &= & \text{10.00 L} \\p_{2}& =& \text{50 kPa}\qquad & V_{2} &= & ?\\\end{array}$

Calculations:

$\begin{array}{rcl}100 \times 10.00 & =& 50V_{2}\\1000 & = & 50V_{2}\\V_{2} & = &\textbf{20 L}\\\end{array}\\\text{The new volume will be } \boxed{\textbf{20 L}}$

26. Ideal Gas Law

We have p, V and n, so we can use the Ideal Gas Law to calculate the volume.

pV = nRT

Data:

p = 101.3 kPa

V = 20 L

n = 5 mol

R = 8.314 kPa·L·K⁻¹mol⁻¹

Calculation:

101.3 × 20 = 5 × 8.314 × T

2026 = 41.57T

$T = \dfrac{2026}{41.57} = \textbf{49 K}\\\\\text{The Kelvin temperature is }\boxed{\textbf{49 K}}$

6 0

3 years ago