Equation of the table is given by
y - 210 = (280 - 210)/(4 - 3) (x - 3)
y - 210 = 70(x - 3)
y - 210 = 70x - 210
y = 70x
When x = 11, y = 70(11) = 770
Equation of the graph is given by
y = 110/2 x = 55x
When x = 11, y = 55(11) = 605
Therefore the value of y in the table is grater than the value of y in the graph by 770 - 605 = 165
Step-by-step explanation:
2x - 5
x+4 / 2x^2 + 3x - 1
- 2x^2 + 8x
0 -5x - 1
- -5x - 20
0 19
Quotient = 2x - 5 + 19/x+4
Remainder = 19/x+4
Answer:
![[11.5-(2.5*3)]^2=16](https://tex.z-dn.net/?f=%5B11.5-%282.5%2A3%29%5D%5E2%3D16)
Step-by-step explanation:
We want to evaluate ![[11.5-(2.5*3)]^2](https://tex.z-dn.net/?f=%5B11.5-%282.5%2A3%29%5D%5E2)
Let us evaluate within the parenthesis first:
![[11.5-(2.5*3)]^2=[11.5-(7.5)]^2](https://tex.z-dn.net/?f=%5B11.5-%282.5%2A3%29%5D%5E2%3D%5B11.5-%287.5%29%5D%5E2)
![\implies [11.5-(2.5*3)]^2=[11.5-7.5]^2](https://tex.z-dn.net/?f=%5Cimplies%20%5B11.5-%282.5%2A3%29%5D%5E2%3D%5B11.5-7.5%5D%5E2)
We again subtract within the bracket to obtain:
![[11.5-(2.5*3)]^2=[4]^2](https://tex.z-dn.net/?f=%5B11.5-%282.5%2A3%29%5D%5E2%3D%5B4%5D%5E2)
This finally gives us:
![[11.5-(2.5*3)]^2=16](https://tex.z-dn.net/?f=%5B11.5-%282.5%2A3%29%5D%5E2%3D16)