Answer:
<em>B</em><em>.</em><em> </em><em>I</em><em>t</em><em> </em><em>i</em><em>s</em><em> </em><em>g</em><em>o</em><em>o</em><em>d</em><em> </em><em>s</em><em>o</em><em>l</em><em>u</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>b</em><em>e</em><em>c</em><em>a</em><em>u</em><em>s</em><em>e</em><em> </em><em>p</em><em>e</em><em>o</em><em>p</em><em>l</em><em>e</em><em> </em><em>w</em><em>i</em><em>l</em><em>l</em><em> </em><em>h</em><em>a</em><em>v</em><em>e</em><em> </em><em>s</em><em>a</em><em>n</em><em>d</em><em> </em><em>t</em><em>o</em><em> </em><em>w</em><em>a</em><em>l</em><em>k</em><em> </em><em>o</em><em>n</em><em> </em><em>a</em><em>l</em><em>o</em><em>n</em><em>g</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>b</em><em>e</em><em>a</em><em>c</em><em>h</em><em>.</em>
Answer:
Starch
Explanation:
Any member of a class of enzymes that catalyze the hydrolysis (splitting of a compound by addition of a water molecule) of starch into smaller carbohydrate molecules such as maltose (a molecule composed of two glucose molecules).
Answer:
Create a punnet square for both problems the 2. with pods yellow is going to be yy while the green pod which would be Gg and you would put that on the side.
1. is with guinea pigs so the top of your square is going to be BB on the side and BB on the top. Genotype is what you are putting the the different squares and the phenotype is the physical trait like black hair or a green pod.
Explanation:
If ΔG is negative, the reaction is always spontaneous.
If ΔG is positive, the reaction is non-spontaneous and will require a sustained input of energy for it occur.
If ΔG is zero, the reaction is at equilibrium and no work can be done.
