<h3>
Answer: PC = 5</h3>
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Work Shown:
AB+BC+CD = AD .... segment addition postulate
BC+BC+CD = AD ... replace AB with BC (since AB = BC)
BC+BC+BC = AD ... replace CD with BC (since BC = BC)
3*BC = AD .... combine like terms
3*BC = 12 .... replace AD with 12
BC = 12/3 .... divide both sides by 3
BC = 4
For right triangle PBC, the legs are BP = 3 and BC = 4. We can use the Pythagorean Theorem to find that the hypotenuse is PC = 5
The steps are shown below
(BP)^2+(BC)^2 = (PC)^2
3^2+4^2 = (PC)^2
9+16 = (PC)^2
25 = (PC)^2
(PC)^2 = 25
PC = sqrt(25)
PC = 5
The other parts of the diagram seem to be thrown in as a distraction.
<span>If you would like to
know how many of each did Jan buy, you can calculate this
using the following two equations:
b ... the number of books
m ... the number of magazines
$16 = b * $3 + m * $2.50 ... 16 = 3 * b + 2.50 * m
b + m = 6 ... b = 6 - m
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</span>16 = 3 * b + 2.50 * m
<span>16 = 3 * (6 - m) + 2.50 * m</span>
16 = 3 * 6 - 3 * m + 2.50 * m
16 - 18 = - 3 * m + 2.50 * m
- 2 = - 0.50 * m /0.50
m = 2 / 0.50
m = 4 magazines
<span>b = 6 - m = 6 - 4 = 2 books</span>
Result: Jan bought 4 magazines and 2 books.
Answer:
Step-by-step explanation:
Hope this helps u!!
Answer:
A(2, -3) and B(3, -2), o(0, 0) Let C(x, y)
Here c divide AB line in the ratio of 1:2
From the line intersection law, we get x=(m1×x2+m2×x1)/(m1+m2)
and y=(m1×y2+m2×y1)/(m1+m2)
where m1=1, m2=2, x1=2, x2=3, y1=-3, y2=-2;
so x=(3+4)/3
or, x=7/3;
y=(-2-6)/3
or, y=-8/3;
so, oc=√((0-7/3)²+(0-(-8/3))²)
oc=3.54