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3 years ago

A piece of electrical pipe conduit has an outer

Mathematics

1 answer:

Umnica [9.8K]3 years ago

4 0

Step-by-step explanation:

inside diameter = 11/2 - 3/16 = 85/16 or 5.3125 inches

Topic: fractions

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1- not every ratoonal number has to terminate

2- Yes, the profuct of any two consecutive interger is positive

Step-by-step explanation:

2 → -3 × -4 = -12

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Solve 3x > 174, and use the interactive number line tool to graph the solution. What is true about the graph? Check all that

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Answer:

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Step-by-step explanation:

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3 years ago

Solve for C. 3c-2c-1=13 PLS HELLLP

uranmaximum [27]

C-1=13 — Combine like terms.
13+1=14 — Cancel the one out.
c=14 — Answer.

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3 years ago

Read 2 more answers

Ok, LAST QUESTION for today! PLEASE SHOW YOUR WORK TY

Margaret [11]

Answer:

(32/5, -48/5)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Terms/Coefficients
Coordinates (x, y)
Solving systems of equations using substitution/elimination

Step-by-step explanation:

Step 1: Define Systems

-4x + 16 = y

2x - 32 = 2y

Step 2: Solve for x

Substitution

Substitute in y: 2x - 32 = 2(-4x + 16)
Distribute 2: 2x - 32 = -8x + 32
[Addition Property of Equality] Add 8x on both sides: 10x - 32 = 32
[Addition Property of Equality] Add 32 on both sides: 10x = 64
[Division Property of Equality] Divide 10 on both sides: x = 32/5

Step 3: Solve for y

Define original equation: -4x + 16 = y
Substitute in x: -4(32/5) + 16 = y
Multiply: -128/5 + 16 = y
Add: -48/5 = y
Rewrite/Rearrange: y = -48/5

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3 years ago

3. for each item, decide whether or not the given expression is defined. for each item that is defined, compute the result. (a)

Sati [7]

The results of given matrices can be obtained using matrix multiplication.

<h3>Find the results of the given matrices:</h3>

Here in the question it is given that,

A = $\left[\begin{array}{ccc}1&-1&2\\3&1&4\end{array}\right]$ , B = $\left[\begin{array}{ccc}2&-1&3\\5&1&2\\4&6&-2\end{array}\right]$ , C = $\left[\begin{array}{ccc}1\\-1\\2\end{array}\right]$ , D = $\left[\begin{array}{ccc}2&-2&3\end{array}\right]$ ,

E = $\left[\begin{array}{ccc}2-i&1+i\\-i&2+4i\end{array}\right]$ , F = $\left[\begin{array}{ccc}i&1-3i\\0&4+i\end{array}\right]$

We have to find AB, BC, CA, CD, $C^{T} A^{T}$ , F², $BD^{T}$ , $A^{T} A$ and FE.

AB = $\left[\begin{array}{ccc}1&-1&2\\3&1&4\end{array}\right]\left[\begin{array}{ccc}2&-1&3\\5&1&2\\4&6&-2\end{array}\right]$

a₁₁ = 1×2 + (-1)×5 + 2×4 = 5, a₁₂ = 1×(-1) + (-1)×1 + 2×6 = 10, a₁₃ = 1×3 + (-1)×2 + 2×(-2) = -3, a₂₁ = 3×2 + 1×5 + 4×4 = 27, a₂₂ = 3×(-1) + 1×1 + 4×6 = 22, a₂₃ = 3×3 + 1×2 + 4×(-2) = 3

AB = $\left[\begin{array}{ccc}5&10&-3\\27&22&3\end{array}\right]$

BC = $\left[\begin{array}{ccc}2&-1&3\\5&1&2\\4&6&-2\end{array}\right]$ $\left[\begin{array}{ccc}1\\-1\\2\end{array}\right]$

a₁₁ = 2×1 + (-1)×(-1) + 3×2 = 9, a₂₁ = 5×1 + 1×(-1) + 2×2 = 8, a₃₁ = 4×1 + 6×(-1) + (-2)×2 = -6

BC = $\left[\begin{array}{ccc}9\\8\\-6\end{array}\right]$

CA, CA is not defined since dimension of the matrices are 3×1 and 2×3

$A^{T}E = \left[\begin{array}{ccc}1&3\\-1&1\\2&4\end{array}\right]\left[\begin{array}{ccc}2-i&1+i\\-i&2+4i\end{array}\right]$

a₁₁ = 1×(2-i) + 3×(-i) = 2-4i, a₁₂ = 1x(1+i) + 3×(2+4i) = 7+13i, a₂₁ = -1×(2-i) + 1×(-i) = -2, a₂₂ = -1×(1+i) + 1×(2+4i) = 1+3i, a₃₁ = 2×(2-i) + 4×(-i) = 4-6i, a₃₂ = 2×(1+i) + 4×(2+4i) = 10+18i

$A^{T}E = \left[\begin{array}{ccc}2-4i&7+13i\\-2&1+3i\\4-6i&10+18i\end{array}\right]$

CD = $\left[\begin{array}{ccc}1\\-1\\2\end{array}\right]$ $\left[\begin{array}{ccc}2&-2&3\end{array}\right]$

a₁₁ = 1×2 = 2, a₁₂ = 1×(-2) = -2, a₁₃ = 1×3 = 3, a₂₁ = -1×2 = -2, a₂₂ = -1×(-2) = 2, a₂₃ = -1×3 = -3,a₃₁= 2×2 = 4, a₃₂ = 2×(-2) = -4, a₃₃ = 2×3 = 6

CD = $\left[\begin{array}{ccc}2&-2&3\\-2&2&-3\\4&-4&6\end{array}\right]$

$C^{T} A^{T} =\left[\begin{array}{ccc}1&-1&2\end{array}\right]\left[\begin{array}{ccc}1&3\\-1&1\\2&4\end{array}\right]$

a₁₁ = 1×1 + (-1)×(-1) + 2×2 = 6, a₁₂ = 1×3 + (-1)×1 + 2×4 = 10

$C^{T}A^{T}=\left[\begin{array}{ccc}6&10\end{array}\right]$

F² = $\left[\begin{array}{ccc}i&1-3i\\0&4+i\end{array}\right]\left[\begin{array}{ccc}i&1-3i\\0&4+i\end{array}\right]$

a₁₁ = i×i + (1-3i)×0 = -1,a₁₂ = i×(1-3i) + (1-3i)×(4+i) = 10-10i, a₂₁= 0×i + (4+i)×0 = 0, a₂₂ = 0×(1-3i) + (4+i)×(4+i) = 15+8i

F² = $\left[\begin{array}{ccc}-1&10-10i\\0&15+8i\end{array}\right]$

$BD^{T}=\left[\begin{array}{ccc}2&-1&3\\5&1&2\\4&6&-2\end{array}\right]\left[\begin{array}{ccc}2\\-2\\3\end{array}\right]$

a₁₁ = 2×2 + (-1)×(-2) + 3×3 = 15, a₂₁ = 5×2 + 1×(-2) + 2×3 = 14, a₃₁ = 4×2 + 6×(-2) + (-2)×3 = -10

$BD^{T}= \left[\begin{array}{ccc}15\\14\\-10\end{array}\right]$

$A^{T} A=\left[\begin{array}{ccc}1&3\\-1&1\\2&4\end{array}\right] \left[\begin{array}{ccc}1&-1&2\\3&1&4\end{array}\right]$

a₁₁ = 1×1 + 3×3 = 10, a₁₂ = 1×(-1) + 3×1 = 2, a₁₃ = 1×2 + 3×4 = 14, a₂₁ = -1×1 + 1×3 = 2, a₂₂ = -1×(-1) + 1×1 = 2, a₂₃ = -1×2 + 1×4 = 2, a₃₁ = 2×1 + 4×3 = 14, a₃₂ = 2×(-1) + 4×1 = 2, a₃₃ = 2×2 + 4×4 = 20

$A^{T} A=\left[\begin{array}{ccc}10&2&14\\2&2&2\\14&2&20\end{array}\right]$

FE = $\left[\begin{array}{ccc}i&1-3i\\0&4+i\end{array}\right]$ $\left[\begin{array}{ccc}2-i&1+i\\-i&2+4i\end{array}\right]$

a₁₁ = i×(2-i) + (1-3i)×(-i) = -2+i, a₁₂ = i×(1+i) + (1-3i)×(2+4i) = 13-i, a₂₁ = 0×(2-i) + (4+i)×(-i) = 1-4i, a₂₂ = 0×(1+i) + (4+i)×(2+4i) = 4+18i

FE = $\left[\begin{array}{ccc}-2+i&13-i\\1-4i&4+18i\end{array}\right]$

Hence we can obtain the results of the required matrices using matrix multiplication.

Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: Let A = $\left[\begin{array}{ccc}1&-1&2\\3&1&4\end{array}\right]$ , B = $\left[\begin{array}{ccc}2&-1&3\\5&1&2\\4&6&-2\end{array}\right]$ , C = $\left[\begin{array}{ccc}1\\-1\\2\end{array}\right]$ , D = $\left[\begin{array}{ccc}2&-2&3\end{array}\right]$ , E = $\left[\begin{array}{ccc}2-i&1+i\\-i&2+4i\end{array}\right]$ , F = $\left[\begin{array}{ccc}i&1-3i\\0&4+i\end{array}\right]$

For each item, decide whether or not the given expression is defined. for each item that is defined, compute the result.

AB, BC, CA, CD, $C^{T} A^{T}$ , F², $BD^{T}$ , $A^{T} A$ and FE

Learn more about matrix here:

brainly.com/question/28180105

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8 0

2 years ago