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Alenkinab [10]
2 years ago
8

If all of the diagonals are drawn from a vertex of a quadrilateral, how many triangles are formed?

Mathematics
1 answer:
sergij07 [2.7K]2 years ago
8 0

Answer:

4

Step-by-step explanation:

From the chioces give it would be 4

But it is actually 8

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Solve for x<br> Write the smaller solution first, and the larger solution second.<br> -x^2-8=-33
kenny6666 [7]

Answer:

x = -5, 5

Step-by-step explanation:

-x^2-8=-33

Add 8 to each side

-x^2-8+8=-33+8

-x^2 = -25

Divide each side by -1

x^2 = 25

Take the square root of each side

sqrt(x^2) = ±sqrt(25)

x = ±5

8 0
3 years ago
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7 years ago father was 7 times as old as his son was. three years hence, he will be three times as old as his son find their pre
EastWind [94]

Answer:

son = 10 , father = 40

Step-by-step explanation:

Let Five years ago the age of son be x years and age of father be 7x years

Present age of son =x+5

Present age of father =7x+5

5 years later their age will (x+10) and (7x+10)

∴7x+10=3(x+10)

7x−3x=20

4x=20

x=5

So, the present age of son=x+5=5+5=10years

and the present age of father=7x+5=35+5=40years

hope it helps you

8 0
3 years ago
How many square centimetres are in 0.0075 square metres
lidiya [134]

Answer:

75 square centimeters

Step-by-step explanation:

Multiply by 10,000

Can you make me brainliest it would help a lot!

4 0
3 years ago
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Two sides of an isosceles triangle have lengths of 4 and 8. What is the length of the third side?
Gnoma [55]

Answer:

8

Step-by-step explanation:

Let's start with a simple fact: two sides of an isosceles triangle must be equal. Let's suppose the missing side is 4

That would mean that 4 + 4 equals 8. You must pick a side that exceeds 8, but you loose the property of 2 sides need to be equal.

So the answer has to be 8. The final size of the sides is 4 8 and 8. 4 and 8 exceed the third side (8).

8 and 8 certainly exceed 4.

3 0
3 years ago
Que
ohaa [14]

Answer:

3g

Step-by-step explanation:

4 0
3 years ago
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