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erik [133]
2 years ago
10

H-12= -6 h=?? someone help asap!! will also mark brainliest!!

Mathematics
2 answers:
topjm [15]2 years ago
3 0

Answer:

h=6

Step-by-step explanation:

to find h add 12 to both sides

Do i earn a brainliest ?:)

wel2 years ago
3 0

Answer:

h=6

Step-by-step explanation:

h-12=-6

+12    +12

h= 6

do inverse operations to get your value of h

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I was on the right track, lol. 280.5 miles.
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Alicia ran 5 miles over the weekend. Approximately how many kilometers did she run? [Use the conversion 1 mile ≈ 1.6 kilometers.
Svet_ta [14]

Answer:

Total distance Alicia run in kilometer = 8 Kilometer

Step-by-step explanation:

Given:

Total distance Alicia run = 5 miles

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A supermarket chain gathers data on the amount they spend on promotional material (e.g., coupons, etc.) and sales revenue genera
vazorg [7]
Answer: The predictor variable in this problem is the amount spent on promotional material.

Explanation: 

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8 0
3 years ago
Someone help me with this question plzzz
asambeis [7]

Answer:

Step-by-step explanation:

As per Janayda,

From the figure attached,

In ΔTRQ,

m∠TRQ + m∠RQT + m∠QTR = 180°

25° + m∠RQT + 35° = 180°

m∠RQT = 180° - 60°

m∠RQT = 120°

Since, m∠RQT + m∠PQT = 180° [Linear pair of angles]

m∠PQT = 180° - m∠RQT

             = 180° - 120°

             = 60°

In right angled triangle TPQ,

m∠TPQ + m∠PQT + m∠PTQ = 180°

90° + 60° + m∠PTQ = 180°

m∠PTQ = 180° - 150°

             = 30°

Similarly, other angles can also be evaluated from the given information.

In ΔQTP and ΔNTP,

TP ≅ TP [Reflexive property]

NP ≅ PQ [Given]

ΔQTP ≅ ΔNTP [By LL postulate for congruence]

Therefore, Janayda is correct.

While Sirr is incorrect.

Since, there is not the enough information to prove ΔRTQ and ΔMTN equal, Isabelle is incorrect.

7 0
2 years ago
Need help with this.​
sweet [91]

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

Let t as y² + 5y .

{y}^{2}  + 5y = t

Rewrite the equation :

t -  \frac{36}{t}  = 0 \\

Multiply sides by t

t \times (t -  \frac{36}{t} ) = t \times 0 \\

{t}^{2}  - 36 = 0

Add sides 36

{t}^{2}  - 36 + 36 = 0 + 36

{t}^{2}  = 36

t = ± \: 6

_________________________________

So :

{y}^{2}  + 5y = 6

Subtract sides 6

{y}^{2}  + 5y - 6 = 6 - 6

{y}^{2}  + 5y - 6 = 0

(y + 6)(y - 1) = 0

y =  - 6 \:  \: or \:  \: y = 1

##############################

{y}^{2} +5y =  - 6

No \:  \:  solution

_________________________________

Thus (( y = 1 )) and (( y = - 6 )) are the roots of the equation .

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

8 0
3 years ago
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