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3 years ago

Can i have some help

Mathematics

1 answer:

Leona [35]3 years ago

8 0

Answer:

y = -1/3x

Step-by-step explanation:

The slope of that are perpendicular lines are negative opposites of each other. If a line has a slope of 3, then a line perpendicular to it will have a slope of (-(1/3)).

Use the equation of a line in point-slope form to solve this;

y = mx + b

where "m" is the slope and "b" is the y-intercept.

Substitute the slope in;

y = (-1/3)x + b

Since it passes through the origin, then it has no y-intercept, therefore the equation of the line is;

y = -1/3x

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Step-by-step explanation:

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3 years ago

The graph of an equation is shown below:

ziro4ka [17]

Answer:

The point $(1,3)$ is a solution of the linear equation

Step-by-step explanation:

we have

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Find the equation of the line AB

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$m=\frac{y2-y1}{x2-x1}$

substitute the values

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$m=\frac{5}{4}$

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we have

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$(x1,y1)=B(1,3)$

substitute

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we know that

If a point is a solution to the equation of the line

then

the point must be satisfy the equation and based on the graph the point must be on the line

Let's check every point.

case A) point $(-2,-3)$

Substitute the value of x and y in the equation of the line

$-3-3=\frac{5}{4}(-2-1)$

$-6=-\frac{15}{4}$ -------> is not true

The point $(-2,-3)$ is not a solution of the linear equation

See the attached figure-------> the point is not on the line

case B) point $(3,1)$

Substitute the value of x and y in the equation of the line

$1-3=\frac{5}{4}(3-1)$

$-2=\frac{10}{4}$ -------> is not true

The point $(3,1)$ is not a solution of the linear equation

See the attached figure-------> the point is not on the line

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Substitute the value of x and y in the equation of the line

$3-3=\frac{5}{4}(1-1)$

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The point $(1,3)$ is a solution of the linear equation

See the attached figure-------> the point is on the line

case D) point $(3,2)$

Substitute the value of x and y in the equation of the line

$2-3=\frac{5}{4}(3-1)$

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The point $(3,2)$ is not a solution of the linear equation

See the attached figure-------> the point is not on the line

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Answer:

Step-by-step explanation:

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