Help me with thissss too

A motel clerk counts his $1 and $10 bills at the end of the day. He finds that he has a total of 55 bills having a combined mo

vfiekz [6]

Answer

39 bills of 1$

16 bills of 10$

Step-by-step explanation:

x-nr of $1

y-nr of $10

x*1+y*10=199

x+y=55 , x=55-y

so I use the substitution method

(55-y)*1+10y=199

55+10y-y=199

-55 -55

9y=144

y=144/9

y=16

so x=55-16

x=39

verify 16*10+39*1=160+39=199

4 0

2 years ago

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The top of a circular vanilla cake with a diameter of 10 inches was covered with frosting. The Martinez family ate half of the c

g100num [7]

Answer:

(22÷7)×5×5=initial area

remaining area= 1/2(initial area)

=(11×25)÷7=39.28 square inches

3 0

3 years ago

A spinner is divided into sections of equal size, some of which are red, some are blue, and the remaining are green. The probabi

Westkost [7]

I think is 35% because 25+10=35

hope this help

plz mark brianliest plz

8 0

2 years ago

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Bones Brothers & Associates prepare individual tax returns. Over prior years, Bones Brothers have maintained careful records

madreJ [45]

Answer:

For this case we have the following info related to the time to prepare a return

$\mu =90 , \sigma =14$

And we select a sample size =49>30 and we are interested in determine the standard deviation for the sample mean. From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard deviation would be:

$\sigma_{\bar X} =\frac{14}{\sqrt{49}}= 2$

And the best answer would be

b. 2 minutes

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

For this case we have the following info related to the time to prepare a return

$\mu =90 , \sigma =14$

And we select a sample size =49>30 and we are interested in determine the standard deviation for the sample mean. From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard deviation would be:

$\sigma_{\bar X} =\frac{14}{\sqrt{49}}= 2$

And the best answer would be

b. 2 minutes

3 0

2 years ago

write a word problem that you can solve by multiplying a mixed number by a whole number. include a solution

Ainat [17]

Jessica is doubling a recipe that calls for 1 1/2 cups of milk. How many cups of milk in total does she need?

2 x 1 1/2 = 3

She needs 3 cups of milk in total.

7 0

3 years ago

Read 2 more answers