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wel
3 years ago
6

Question 1

Mathematics
1 answer:
astra-53 [7]3 years ago
4 0

Answer: 1

Step-by-step explanation:

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Find the flux of the vector field F = 〈e-z,4z,6xy) across the curved sides of the surface S = {(x,y,z): z= cos y, lys π, 0sxs4}
Len [333]

I'll go ahead and assume you meant to say that <em>S</em> is the surface given by

S = \left\{(x,y,z) \mid z = \cos(y)\text{ with } 0\le y\le \pi\text{ and }0\le x\le4\right\}

This immediately gives us a parameterization for the surface,

\vec r(x, y) = \left\langle x, y, \cos(y)\right \rangle

The upward-pointing normal vector to this surface is then

\vec n = \dfrac{\partial\vec r}{\partial x} \times \dfrac{\partial\vec r}{\partial y} = \left\langle0,\sin(y),1\right\rangle

Then the flux of \vec F(x,y,z) = \left\langle e^{-z}, 4z, 6xy\right\rangle across <em>S</em> is

\displaystyle \iint_S \vec F(x,y,z)\cdot\mathrm d\vec s = \int_0^4\int_0^\pi \vec F(x,y,\cos(y))\cdot\vec n\,\mathrm dy\,\mathrm dx \\\\ = \int_0^4\int_0^\pi \left\langle e^{-\cos(y)},4\cos(y),6xy\right\rangle \cdot \left\langle0,\sin(y),1\right\rangle \,\mathrm dy\,\mathrm dx \\\\ = \int_0^4\int_0^\pi (4\sin(y)\cos(y)+6xy)\,\mathrm dy\,\mathrm dx \\\\ = 2 \int_0^4\int_0^\pi (\sin(2y) + 3xy)\,\mathrm dy\,\mathrm dx = \boxed{24\pi^2}

8 0
3 years ago
The U.S. Department of Agriculture guarantees dairy producers that they will receive at least $1.00 per pound of butter they sup
yaroslaw [1]

Answer:

a. In the butter market, the monthly <u>equilibrium quantity is 95 million pounds</u> and the <u>equilibrium price is $1.2 per pound</u>.

b. The correct option is <u>zero</u>.

c. See the attached excel file for the new supply schedule.

d. The monthly surplus created by the price support program is 18 million pounds given the new supply of butter.

Step-by-step explanation:

Note: This question is not complete. A complete question is therefore provided in the attached Microsoft word file.

a. In the butter market, the monthly equilibrium quantity is million pounds and the equilibrium price is $ per pound.

At equilibrium, quantity demanded must be equal with the quantity supplied.

In this question, equilibrium occurs at the price of $1.20 per pound and quantity of 95 million pounds.

Therefore, in the butter market, the monthly equilibrium quantity is 95 million pounds and the equilibrium price is $1.2 per pound.

b. What is the monthly surplus created in the wholesale butter market due to the price support (price floor) program?

Price floor refers to a government price control on the lowest price that can be charged for a commodity.

It should be noted that for a price floor to be binding, it has to be fixed above the equilibrium price.

Since the price floor of $1 per pound is lower than the equilibrium price of $1.2 per pound, the price floor will therefore not be binding. As a result, the market will still be at the equilibrium point and the monthly surplus created in the wholesale butter market due to the price support (price floor) program will be zero.

Therefore, the correct option is <u>zero</u>.

c. Fill in the new supply schedule given the change in the cost of feeding cows.

Since a decrease in the cost of feeding cows shifts the supply schedule to the right by 40 million pounds at every price, this implies that there will be an increase in supply by 40 million at each price.

Note: Find attached the excel file for the new supply schedule.

d. Given the new supply of butter, what is the monthly surplus of butter created by the price support program?

Since the price floor has been fixed at $1 per pound by the price support program, we can observe that the quantity demanded is 101 million pounds and quantity supplied is 119 million pounds at this price floor of $1. The surplus created is then the difference between the quantity demanded and quantity supplied as follows:

Surplus created = Quantity supplied - Quantity demanded = 119 - 101 = 18 million pounds

Therefore, the monthly surplus created by the price support program is <u>18 million pounds</u> given the new supply of butter.

Download xlsx
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark"> xlsx </span>
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark"> docx </span>
4 0
4 years ago
See attachment please
Nastasia [14]

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Dude why is the picture a

Step-by-step explanation:

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This probability distribution shows the
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Answer is 0.14.

Step-by-step explanation:

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50 POINTS PLEASE HELP show work answer all 3
SCORPION-xisa [38]

Answer:

b.) The graph's x-intercepts are similar to ½(x - 5)(x + 2).

a.) [-2, 0], [5, 0]

__________________________________________________________

b.) The graph has a maximum value because the graph opens down [-2 = <em>A</em>].

a.) [-3, -4]

__________________________________________________________

d) [0, -5]

c) -2 = x

b) [-2, -9] → [<em>h</em>, <em>k</em>]

a) -1, 5 = x

Explanation:

b) Both graphs have the binomial of [x - 5][x + 2], so the x-intercepts never altered.

a) Set the binomial equal to zero, and you will get your x-intercepts of [-2, 0] and [5, 0].

__________________________________________________________

b) When <em>A</em> is negative, your graph will have a <em>maximum value</em> [<em>opens down</em>], whereas when <em>A</em> is positive, your graph will have a <em>minimum value</em> [<em>opens up</em>].

a) According to the <em>Vertex Formula</em>, <em>y = A</em>[<em>X - H</em>]<em>² + K</em>, [<em>H</em>, <em>K</em>] represents the vertex, plus, -H gives you the OPPOSITE TERMS OF WHAT THEY REALLY ARE, so be EXTREMELY CAREFUL labeling your vertex. Additionally, K gives you the NORMAL TERMS.

__________________________________________________________

d) The <em>y-intercept</em> is your C-term, so in this case, it is [0, -5].

c) To find the <em>axis of symmetry</em>, use this formula:

\frac{-b}{2a} = x

Whatever the opposite of your B-term is, you take that and divide it by twice your A-term.

b) To find the vertex, in this case, you have to go from <em>Standard Form</em> to <em>Vertex Form</em> by completing the square, using this formula to get part of your new C-term:

[\frac{b}{2}]^{2}

When done, you get this:

y = {x}^{2} + 4x + 4 \\  \\ y = [x + 2]^{2}

Then, you have to deduct some number from 4 that gave you -5 in the first place, and that integer is -9. So, here is the result:

y = [x + 2]^{2} - 9

From here, we can see that our vertex is [-2, -9].

a) When the binomial is set to equal to zero, you get this:

{x}^{2} + 4x - 5 \\  \\ [x - 1][x + 5] = 0 \\  \\ 1, \: -5 = x

e) <em>See above photograph</em>

I am joyous to assist you anytime.

6 0
4 years ago
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