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Firlakuza [10]
3 years ago
7

Helpp show work plsss

Mathematics
1 answer:
gulaghasi [49]3 years ago
8 0

Answer:

everyone gets 0.5 lbs of sunflower seeds because 6÷3=0.5

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Two consecutive even Integers whose product is 80
Papessa [141]
8 and 10 hope this helps
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The U.S based motorcycle manufacturer says that it expects to build 138,000 motorcycles this year, up from 128,000 last year. Fi
MrMuchimi
138,000/ 128,000 = 7.8125% Just divide new value into old value
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4 years ago
If f(x) = 2x-7, what is the equation for f^-1(x)?
quester [9]
F= -1
2x (-1)-7= -2-7= -9
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4 years ago
3 + 11 . (8 - 4) ÷ (5 + 6) - 4
Irina-Kira [14]

Answer:

3

Step-by-step explanation:

3 + 11 ⋅ ( 8 − 4 ) ÷ ( 5 + 6 ) − 4

 Subtract  4  from  8 .

3 + 11 ⋅ 4 ÷ ( 5 + 6 ) − 4

Multiply  11  by  4 .

3 + 44 ÷ ( 5 + 6 ) − 4

Find the common denominator.  

Add  5  and  6 .

3 + 44 ÷ 11 − 4

Write  3  as a fraction with denominator  1 .

3/ 1 + 44 ÷ 11 − 4

Multiply  3/ 1  by  11/ 11 .

3/ 1 ⋅ 11 /11 + 44 ÷ 11 − 4

Multiply  3/ 1  and  11 /11 .

3 ⋅ 11 /11 + 44 ÷ 11 − 4

Write  − 4  as a fraction with denominator  1 .

3 ⋅ 11 /11 + 44 ÷ 11 +  − 4 /1

Multiply  − 4 /1  by  11 /11 .

3 ⋅ 11 /11 + 44 ÷ 11 + − 4 /1  ⋅ 11 /11

Multiply  

− 4 /1  and  11 /11 .

3 ⋅ 11 /11 + 44 ÷ 11 +   − 4 ⋅ 11 /11

Combine the numerators over the common denominator.

3 ⋅ 11 + 44 − 4 ⋅ 11 /11

Simplify each term.  

Multiply  3  by  11 .

33 + 44 − 44 ⋅ 11/ 11

Multiply  − 4  by  11 .

33 + 44 − 44 /11

Simplify the expression.  

Add  33  and  44 .

77 − 44/ 11

Subtract  44  from  77 .

33 /11

Divide  33 by  11 .

3

5 0
3 years ago
Read 2 more answers
Please tell me the outlier of each set of numbers (3 sets only)!
yulyashka [42]

Hey there!

An outlier in a data set is a number that is WAY larger or WAY smaller than the others in the data set, or does not really fit in the specified "range". In the first one, 452 is way greater than everything else, so it would be the outlier.

In the second data set, 5 would be our outlier because it is much smaller than all the other numbers.

In the last data set, the numbers are pretty close together, but we need to find one that isn't inside the small range. 0.201 appears to be the outlier in this case.

Therefore, here are your answers :)

15: 452

16: 5

17: 0.201

I hope this helps!

5 0
3 years ago
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