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ella [17]
3 years ago
6

Please help me!!!!!!!!!!i need to finish by tonight!!

Mathematics
1 answer:
Viktor [21]3 years ago
4 0
Number 3.
opens up
vertex (1,2)
idk maybe because it is on the right side. its positive

number 4.
opens up as well
Vertex (-2,0)
no because it is negative and on the left. Idk just a guess for this one
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Fraction that less than 5/6 and has a denominator of 8
AnnyKZ [126]
A fraction that is less than 5/6 and has a denominator of 8 would be 4/8 because if you compare 4/8 and 5/6 4/8 is less than 5/6. (to compare this two fractions you need to make them have the same denominator so they would end up been 4/8=12/24
5/6=20/24
And 12/24 is smaller than 20/24
(Besides 4/8 is half and 5/6 is more than half
3 0
3 years ago
There are 90 girls and 60 boys Participating in a race. The coach separates them into two equal groups made of all girls or or b
Lady_Fox [76]
90/2 is 45.. 60/2 is 30.. 30+45=75... 75 students would be able to be in each of the 2 groups, each containing 45 girls and 30 boys ... Hope I helped (:
7 0
3 years ago
What's the value? A.-20 B.-4 C.4 D.20
ale4655 [162]

Answer:

<h2>-4</h2>

Option B is the correct option.

Step-by-step explanation:

{(4 - 2)}^{3}  - 3 \times 4

Subtract the numbers

=  {(2)}^{3 } - 3 \times 4

Multiply the numbers

=  {(2)}^{3}  - 12

Evaluate the power

= 8 - 12

Calculate the difference

=  - 4

Hope this helps..

Best regards!!

4 0
2 years ago
Read 2 more answers
What is the diffrence between 6 thirty-sixes and 4 thirty-sixes.?
Lilit [14]
6 thirty-sixes -4 thirty-sixes = 2 thirty-sixes
2 thirty-sixes = 2•36 = 72
6 0
3 years ago
I have the first part but I don't know how to do the second part<br><br> h e l p
Debora [2.8K]

\bf \begin{array}{cll} \stackrel{ordinal}{position}&\stackrel{term}{value}\\ \cline{1-2} 1&12\\ 2&12+d\\ 3&12+d+d\\ 4&12+d+d+d\\ &12+3d \end{array}\qquad \implies ~\hfill \begin{array}{llll} \stackrel{\textit{4th term}}{12+3d}~~=~~\stackrel{\textit{4th value}}{3}\\\\ 3d=-9\implies d = \cfrac{-9}{3}\\\\ \stackrel{\textit{common difference}}{d = -3} \end{array}

well, we know the common difference is -3, to go from the 4th term to the 8th term, we need to add "d" 4 times or namely 3+4(-3), likewise to go from the 13th term to the 19th term we have to add "d" 6 times, or namely -24 + 6(-3).

\bf \stackrel{\textit{8th term}}{3+4(-3)}\implies 3-12\implies -9 \\\\\\ \stackrel{\textit{19th term}}{-24 + 6(-3)}\implies -24-18\implies -42

3 0
2 years ago
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