Answer:
(1) 102.55 in
(2) 316.69 in²
Step-by-step explanation:
Applying (1)
a² = b²+c².............. Equation 1
Given: a = 25 in, b = 20 in,
25² = 20²+b²
b² = 25²-20²
b² = 225
b = √225
b = 15 in
b = diameter of the semicircle
The lenght of the semicircle = πd/2 = 3.14×15/2 = 23.55 in
Therefore,
P = 37+25+17+23.55 = 102.55 in
(2) Applying,
A = Area of the tripezium- area of the semi circle
A = [h(a+b)/2]-πh²/8.............. Equation 2
Given; h = 15 in, a = 17 in, b = 37 in
A = (15(17+37)/2)-(3.14×15²/8)
A = 405-88.31
A = 316.69 in²
Got you. So we will use the basic formula for the area of a rectangle and insert variable values. (^_^)
Area= Width(Height) ----------- Insert values of width and height [width = (x-1)
, height = (x+9)]
Area= (x-1)(x+9) ) -------------- Then expand if needed?
= x² +8x -9
Answer: for the on your own the equation is y=2x for the outputs on the other thing just add the numbers up
Step-by-step explanation:
Answer:
its point D hope this helps :)
Answer: AB will be parallel to A'B'.
Step-by-step explanation: We know the definition of dilation about the centre. It is defined as the enlargement or shrinken of the original figure keeping the centre of dilation or the figure as fixed.
We are given ΔUVW and AB is perpendicular to UW. Now, if we dilate the triangle about the origin, then the triangle will either enlarge or shrink keeping the centre fixed.
Let us consider the enlarged triangle, ΔU'V'W' as shown in the attached figure. Also, line AB will move to the new position A'B'. We can clearly see that both the lines are parallel to each other.
Thus, the line segments AB and A'B' will be parallel too each other.