The a metal tank containing hydrogen gas has a pressure gauge that reads 575 psi, 120 pressure inside of the tank.
What is pressure gauge?
A device used to measure a fluid's (liquid or gas') state by calculating the force the fluid would apply to a unit area if it were at rest.
What is pressure?
The force of all gas particle/wall collisions divided by the surface area of the wall is the definition of pressure (P): One of the fundamental quantifiable variables.
Therefore, a metal tank containing hydrogen gas has a pressure gauge that reads 575 psi, 120 pressure inside of the tank.
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Answer:
Option c → Tert-butanol
Explanation:
To solve this, you have to apply the concept of colligative property. In this case, freezing point depression.
The formula is:
ΔT = Kf . m . i
When we add particles of a certain solute, temperature of freezing of a solution will be lower thant the pure solvent.
i = Van't Hoff factor (ions particles that are dissolved in the solution)
At this case, the solute is nonvolatile, so i values 1.
ΔT = Difference between fussion T° of pure solvent - fussion T° of solution.
T° fussion paradichlorobenzene = 56 °C
T° fussion water = 0°
T° fussion tert-butanol = 25°
Water has the lowest fussion temperature and the paradichlorobenzene has the highest Kf. But the the terbutanol, has the highest Kf so this solvent will have the largest change in freezing point, when all the molalities are the same.
Answer:
Explanation:
The first thing we need to do is to convert the wavelength to meters. We should remember that 1 meter is 1x10^9 nm so:
∧ = 150 nm / 1x10^9 nm = 1.5x10^-7 m
The formula for Energy in this case is:
E = hc/∧
We already know that c is the speed of light, which is 3x10^8 m/s and h is the planck constant which is 6.63x10^-34 J.s
Replacing data in the above formula:
E = 6.63x10^-34 * 3x10^8 / 1.5x10^-7 = 1.33x10^-18 J per photon.
Now finally to calculate the carbon atoms present in the sample, let's calculate the number of photons:
n° of photons = 1.98x10^5 / 1.33x10^-18
n° of photons = 1.49x10^23 photons
The exercise states that one atom emits on photon, so we can assume that this final result would be the number of carbon atoms present in the sample.
