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3 years ago

Will give BRAINLIEST!!! Will give BRAINLIEST

Chemistry

1 answer:

pantera1 [17]3 years ago

6 0

Answer:

The calculated concentration of acid will be higher than the actual concentration of acid

Explanation:

We have information that all enable us to calculate the concentration of KOH in the solution. From the question, we have;

Mass of KOH= 14.555g

Molar mass of KOH= 56.1056 g/mol

Volume of solution= 500 ml

Number of moles of KOH= ???

From;

m/M= CV

m= mass of KOH

M= molar mass of KOH

C= concentration of KOH solution

V= volume of solution

Substituting values;

14.555g/56.1056 g/mol = C× 500/1000

0.259 moles = 0.5C

C= 0.259/0.5

C= 0.518 M

If the acid is HA, the reaction equation is;

KOH(aq) + HA(aq) ----> KA(aq) + H2O(l)

The concentration of the acid is usually determined via titration. This involves delivering a particular volume of acid in a burette into the base and watching out for the volume of acid used at end point. If there are air bubbles in the burette, then more volume of acid is recorded than that actually used and this will make the calculated concentration of the acid to be higher than the actual concentration of acid present.

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Draw graphs representing Boyle’s law, Charles’s law, and Gay-Lussac’s law for a fixed amount of gas. Make sure that you label ea

dem82 [27]

Answer:

Explanation:

i) represents Boyle s law

ii) represents Charles' law

III) represents Gay Lussacs' law

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3 years ago

Calculate the enthalpy change for the reaction 2 hcl → h2 + cl2 1. +184 kj/mol of rxn 2. +428 kj/mol of rxn 3. 0 kj/mol of rxn 4

lesantik [10]

Below is the list of enthalpies of formation of the compounds involved in the chemical reaction.

HCl: -92.3 kJ/mol
H2: 0
Cl2: 0

Both H2 and Cl2 do not have enthaply of formation because they are pure substances.

Since, in the reaction there are 2 moles of HCl,
Enthalphy of formation = enthalpy of products - enthalphy of reactant/s
= 0 - (-92.3)(2) = +184.6 kJ

Hence, the answer is the first choice.

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3 years ago

lozanna [386]

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Explanation:

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3 years ago

Question 22

ruslelena [56]

Answer:

O2, oxygen.

Explanation:

Hello.

In this case, for the undergoing chemical reaction, we need to compute the moles of CO2 yielded by 85 g of CH4 (molar mass = 16 g/mol) and by 320 g of O2 (molar mass 32 g/mol) via the following mole-mass relationships:

$n_{CO_2}^{by\ CH_4}=85gCH_4*\frac{1molCH_4}{16gCH_4} *\frac{1molCO_2}{1molCH_4} =5.3molCO_2\\\\n_{CO_2}^{by\ O_2}=320gO_2*\frac{1molO_2}{32gO_2} *\frac{1molCO_2}{2molO_2} =5molCO_2$

Considering the 1:2:1 among CH4, O2 and CO2. Therefore, since 320 g of O2 yield the smallest amount of CO2 we infer that the limiting reactant is O2.

Best regards.

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3 years ago

An alkaline battery produces electrical energy according to the following equation.

VashaNatasha [74]

a) Given reaction:

Zn + 2MnO2 + H2O → Zn(OH)2 + Mn2O3

1 mole of Zn combines with 2 moles of MnO2

Now:

# moles Zn present = 17.5/65.38 = 0.2677 moles

# moles of MnO2 present = 31.0/86.94 = 0.3566 moles

Since # moles of MnO2 is less than Zn i.e. it is not present in the 2:1 ratio (MnO2:Zn), MnO2 will be the limiting reagent

b) Based on stoichiometry:

2 moles of MnO2 produces 1 mole of Zn(OH)2

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4 0

3 years ago