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3 years ago

A cylinder has a base radius of 8 cm and a height of 7 m. What is its volume in cubic centimeters to the nearest 10th Place

Mathematics

1 answer:

gayaneshka [121]3 years ago

7 0

Answer:

1407.4

Step-by-step explanation:

volume = π · r^2 · h

you plug in the values and get => 1,407.434

Rounded to the nearest tenth = 1407.4

Hope this Helps!

Please mark as brainiest if correct (o_o)

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2. The volume of a cylinder varies jointly with its height and the square of the radius. A 7.85 cubic inch spice container is 2.

Natali [406]

Answer:

Volume=21.195 cubic inch

Step-by-step explanation:

The volume of a cylinder varies jointly with its height and the square of the radius is expressed as

V∝hr^2

Introducing our constant of proportionality,K we have that

V =Khr^2

Given that A 7.85 cubic inch spice container is 2.5 inches tall and has a radius of 1 inch. We have that

V =Khr^2

7.85=K 2.5 X 1^2

K=7.85/2.5 x1

K=3.14

Given that another spice container is 3 inches tall with a radius of 1.5 inches, Volume=?

V =Khr^2

V=3.14 X 3 X 1.5^2

V=21.195 cubic inch

6 0

3 years ago

What is the value of x in the figure shown below?<br> PLEASE HELP ME ):

sertanlavr [38]

Answer:

40 degrees

Step-by-step explanation:

4 0

3 years ago

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The operation manager at a tire manufacturing company believes that the mean mileage of a tire is 44,663 miles, with a standard

expeople1 [14]

Answer:

The probability is $P(| \= X- \mu| < 199 ) = 0.733$

Step-by-step explanation:

From the question we are told that

The mean mileage of a tire is $\mu = 44663$

The standard deviation is $\sigma = 2594$

The sample size is n = 209

Generally the standard error of mean is mathematically represented as

$\sigma_{x} = \frac{\sigma}{\sqrt{n} }$

=> $\sigma_{x} = \frac{2594}{\sqrt{209} }$

=> $\sigma_{x} = 179.4$

Generally the probability that the sample mean would differ from the population mean by less than 199 miles is mathematically represented as

$P(| \= X- \mu| < 199 ) = P(|\frac{\= X - \mu}{ \sigma_{x}}| < \frac{199}{ 179.4})$

$\frac{\= X -\mu}{\sigma } = Z (The \ standardized \ value\ of \ \= X )$

=> $P(| \= X- \mu| < 199 ) = P(|Z| < \frac{199}{ 179.4})$

=> $P(| \= X- \mu| < 199 ) = P(|Z|< 1.11)$

=> $P(| \= X- \mu| < 199 ) = P(-1.11 \le Z \le 1.11 )$

=> $P(| \= X- \mu| < 199 ) = P(Z \le 1.11 ) - P( Z \le -1.11 )$

From the z table the area under the normal curve to the left corresponding to 1.11 and -1.11 is

$P(Z \le 1.11 ) = 0.8665$

and

$P(Z \le - 1.11 ) = 0.1335$

$P(| \= X- \mu| < 199 ) = 0.8665 - 0.1335$

=> $P(| \= X- \mu| < 199 ) = 0.733$

8 0

3 years ago

99/100 * 0.4......<br> please solve this ASAP

nekit [7.7K]

Answer is 0.396
To make it easier, I converted the fraction to a decimal (0.99), then multiplied 0.99 • 0.4 which will equal 0.396 or 99/250.

5 0

3 years ago

The system, 6x - 4y = 5 and 9x - 6y = 5, is consistent.<br> True of False

enyata [817]

False, I'm pretty sure

8 0

4 years ago

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