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3 years ago

I NEED IT NOW!!! I ALSO NEED YOUR WORK OF HOW YOU GET YOUR ANSWER !! THANK YOU!

Mathematics

1 answer:

Mars2501 [29]3 years ago

3 0

Answer:

Solve the rational equation by combining expressions and isolating the variable

All real numbers

Interval Notation:

−∞,∞)

Step-by-step explanation:

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H(x) = –x2 + 1; Find h(–6)

babunello [35]

Answer:

h(-6)= -(-6)2+1= 12+1= 13.

5 0

3 years ago

Two friends, Alejandro and Mia, agreed to split the check at a restaurant. Alejandro ordered $12 worth of food and Mia ordered $

kvasek [131]

Cost of Alejandro's food = $12

Tip paid by Alejandro = 20% of his bill = 20% of 12 = 2.4

Cost of Mia's food = $18

Tip paid by Mia = 15% of his bill = 15% of 18 = 2.7

Total Tip Paid = 2.4+2.7 = 5.1

Total Check Amount = 12 + 18 = 30

Total tip paid by Alejandro and Mia is r% of the total check amount.

So, we need to determine what % of 30 is equal to 5.1%

⇒ r% × 30 = 5.1

⇒ r% = 5.1 / 30

⇒ r% = 17%

Hence, r is 17%

8 0

3 years ago

Brooke has to set up 70 chairs for the class talent show. But, there is not room for more than 20 rows.

den301095 [7]

If there are 70 chairs but only 20 rows then that means he will have to set up 3.5 chairs per row, or Brook could set up 14 rows with 5 chairs in each row.

Srry if that didn't help but that's what i got from that.

4 0

3 years ago

A random sample of 77 fields of durum wheat has a mean yield of 27.427.4 bushels per acre and standard deviation of 5.755.75 bus

xz_007 [3.2K]

Answer:

[ 21.79, 33.0 ]

Step-by-step explanation:

Given:

Sample size, n = 7

Sample mean, μ = 27.4

Standard deviation, σ = 5.75

Confidence level is 99%

also, population is normal i.e normally distributed

Thus,

Confidence interval = μ ± $z\frac{\sigma}{\sqrt n}$

For confidence level of 99%

z-value = 2.58

Therefore,

Lower limit of Confidence interval = μ - $2.58\times\frac{5.75}{\sqrt{7}}$

Lower limit of Confidence interval = 27.4 - $2.58\times\frac{5.75}{\sqrt{7}}$

Lower limit of Confidence interval = 21.79

Upper limit of Confidence interval = μ + $2.58\times\frac{5.75}{\sqrt{7}}$

Upper limit of Confidence interval = 27.4 + $2.58\times\frac{5.75}{\sqrt{7}}$

Upper limit of Confidence interval = 33.00

Hence, confidence interval = [ 21.79, 33.0 ]

5 0

3 years ago

How do you factor 8x + 56

____ [38]

$8x + 56 \\ \\ GCF = 8 \\ \\ 8( \frac{8x}{8} + \frac{56}{8} ) \\ \\ 8(x + 7) \\ \\$

The final result is: 8(x + 7).

4 0

3 years ago

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