We have a line y = 1/3x -6
We want a line that is perpendicular to this line
Perpendicular lines have slopes that multiply to -1
1/3 * m = -1
3 * 1/3 *m = -1 * 3
m = -3
The slope of the perpendicular line is -3
y = mx+b where m is the slope and b is the y intercept
y = -3x+b
We have a point on the line ( 7 ,-23)
Substitute this point into the equation
-23 = -3(7)+b
-23 = -21+b
Add 21 to each side
-23+21 = -21+21+b
-2 = b
y = -3x-2
In slope intercept form, the line perpendicular passing through (7,-23) is
y = -3x-2
Answer:
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Step-by-step explanation:
Answer:
x=20, g=100, f=80
Step-by-step explanation:
when ever somthing is suplementary it means the the answer will euqal to 180 degrees. That means your equation is going to be
3x+40+5x-20=180
8x+20=180
8x=160
x=20
Finding g
3(20)+40
60+40
g=100
FInding f
5(20)-20
100-20
f=80
Answer:
(-2, -1)
Step-by-step explanation:
This is a quadratic equation in standard form, and a = 1, b = 4 and c = 3.
The x-coordinate of the vertex is given by the formula
-b -4
x = --------- which here has the numerical value x = -------- = -2
2a 2
Finally, we evaluate y=x^2+4x+3 at x = -2 to find the y-coordinate of the vertex:
y = (-2)^2 + 4(-2) + 3 = -1
The vertex is at (-2, -1).
