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3 years ago

10 points slope of (-2,-4) and (6,7) (explain)

Mathematics

1 answer:

Finger [1]3 years ago

4 0

Answer:

11/-8

Step-by-step explanation:

-2-6=-8

-4-7=11

then flip

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Currently, in Littlefield, jobs arrive at 12 per day and you have (just) enough capacity at each station (i.e., the departure ra

OlgaM077 [116]

Answer:

The WIP limit is 0.50 days.

Step-by-step explanation:

The Computation of WIP limits:

to begin with, it is required to compute the process and procedure efficiency which will be computed as follows:

Value Added Time = 12 days (arriving time)

Non-Value-Added Time = 12 days (departure time)

Efficiency = Value Added / (Value Added + Non-Value Added)

= 12 / (12+12)

= 12 / 24

= 0.50 or 50%

the most obligatory throughput time will be 0.25 days to realize the profits

WIP limit = Throughput time / Efficiency

= 0.25 / 50%

= 0.50 days.

The WIP limit is 0.50 days.

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3 years ago

In a writing competition, the first place winner receives 1/2 of the prize money. The second runner up receives 1/4 of what the

worty [1.4K]

Answer:

10,000 is the total amount of.money that was distributed

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2 years ago

What's the answer for 13x-37+2x+13

USPshnik [31]

Answer:

11x+50

Step-by-step explanation:

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3 years ago

Read 2 more answers

1) find the equation of the line parallel to

In-s [12.5K]

Answer:

1) The equation of the line parallel to x-5y=6 and through (4,-2) is 5y = x -14

2) The equation of the line perpendicular to y= -2/5x + 3 and through (2,-1) is 2y = 5x -12

Solution:

1) find the equation of the line parallel to x-5y=6 and through (4,-2).

Given, line equation is x – 5y = 6

We have to find the line equation that is parallel to given line and passing through the point (4, -2)

Now, let us find slope of the given line.

$\text { Slope }=\frac{-x \text { coefficient }}{y \text { coefficient }}=\frac{-1}{-5}=\frac{1}{5}$

Now, we know that, slope of parallel lines are equal.

So, slope of required line is 1/5 and it passes through (4, -2)

Now, using point slope form

$y-y_{1}=m\left(x-x_{1}\right) \text { where } m \text { is slope and }\left(x_{1}, y_{1}\right) \text { is point on line. }$

$y-(-2)=\frac{1}{5}(x-4) \rightarrow 5(y+2)=x-4 \rightarrow 5 y+10=x-4 \rightarrow x-5 y=14$

Hence, the line equation is 5y = x -14

2) find the equation of the line perpendicular to y= -2/5x + 3 and through (2,-1)

$\text { Given, line equation is } y=-\frac{2}{5} x+3 \rightarrow 5 y=-2 x+15 \rightarrow 2 x+5 y=15$

We have to find the line equation that is perpendicular to given line and passing through the point (2, -1)

Now, let us find slope of the given line.

$\text { Slope }=\frac{-x \text { coefficient }}{y \text { coefficient }}=\frac{-2}{5}=-\frac{2}{5}$

Now, we know that, product of slopes of perpendicular lines equals to -1.

So, slope of required line $\times$ slope of given line = -1

slope of required line = $-1 \times \frac{5}{-2}=\frac{5}{2}$

And it passes through (2, -1)

Now, using point slope form

$\begin{array}{l}{\text { Line equation is } y-(-1)=\frac{5}{2}(x-2) \rightarrow 2(y+1)=5(x-2)} \\\\ {\rightarrow 2 y+2=5 x-10 \rightarrow 5 x-2 y=12}\end{array}$

Hence, the line equation is 2y = 5x -12

4 0

3 years ago

What are the slopes of the two lines? green has two yellow dots.

IrinaVladis [17]

Answer:

-7(1/7) = -1

Step-by-step explanation:

4 0

3 years ago