By the quadratic formula, the <em>solution</em> set of the <em>quadratic</em> equation is formed by two <em>real</em> roots: x₁ = 0 and x₂ = - 12.
<h3>How to find the solution of quadratic equation</h3>
Herein we have a <em>quadratic</em> equation of the form a · m² + b · m + c = 0, whose solution set can be determined by the <em>quadratic</em> formula:
x = - [b / (2 · a)] ± [1 / (2 · a)] · √(b² - 4 · a · c) (1)
If we know that a = - 1, b = 12 and c = 0, then the solution set of the quadratic equation is:
x = - [12 / [2 · (- 1)]] ± [1 / [2 · (- 1)]] · √[12² - 4 · (- 1) · 0]
x = - 6 ± (1 / 2) · 12
x = - 6 ± 6
Then, by the quadratic formula, the <em>solution</em> set of the <em>quadratic</em> equation is formed by two <em>real</em> roots: x₁ = 0 and x₂ = - 12.
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Answer:
Hi! The answer to your question is 
Step-by-step explanation:
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It would be positive 1/3 because if you move to the right one on your bottom point and up 3 it gives you +1/3
Answer:
A = 624
B = 14.76 or 14.8 or 15inches
Standard form in polynomial for Area = 26 x 24 = .624in^2.....
2(5 + 8) x 2( 5 + 7)
26 x 24 = 624 in^2
This is because the rectangle width indifference is 1/10th of the length measuring 2inches more, then we see both sides of the frame are equal to 2inches and match this measure for x = 2inches both width and length. We add 4 to each side 22 x 20 + 4x^2 we separate 4x^2 into 4x both sides, this has become 26 x 24 = 624in^2
as 4 was added each side.
Question 2.
We find the width is shown left to right in rectangles, they are the sides.
So Area 4 x 24 = 96in^2
or 6.5 of the 24 = 24/6.5 = 3.69 inches
26 /6.5 = scale of 6.5: 26 = 4 inches
Therefore Area = 3.69 x 4 = 14.76
if it was square frame it would be 16inches
Go for 14.76in^2 as ithe question says 4 inches and it becomes, a replaced width only and it must be still to scale as shown above with 24/6.5 = 3.69 so 3,69 x 4 = 14.76. Last resort would be that the length as kept at 24 x 4 = 96 and in this response it does exactly what the question asks the width changes only.
