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1 answer:
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Answer:
0.999
Step-by-step explanation:
At least 1 correct means, 1 correct, 2 correct, 3 correct ... until 10 correct. That would be a long process to calculate.
<em>Instead we use the complement rule to calculate.</em>
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<em>So we need to find P(x<1). So this is getting 0 answers correct, or 10 incorrect.</em>
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In true false question, probablity of correct is 1/2 and incorrect is 1/2, hence,
Probability of 10 incorrect is (1/2)^10
Thus,
So the answer is 0.999 (rounded to nearest thousandth)
Answer:
Hope this is what you are looking for! :)
Complete question:
Consider a class of 20 students consisting of 5 sophomores, 8 juniors, and 7 seniors. A math instructor assigns a group project in each of the scenarios below, the instructor selects 5 consecutive students from this class, keeping track (in order) of the level of the student that he gets.
1a. How many possible outcomes are in the sample space S? (An outcome is a 5- tuple of students.)
Let A2 denote the event that exactly 2 of the selected students are sophomore, A5 denote the event that exactly 5 of the selected students are the juniors, and A4 denote the event that exactly 4 of the selected students are seniors.
1b. Find the probabilities of each of these three events. A2, A5, A4
1c. Do the events A2, A5, A4 constitute a partition of the sample space?
Answer:
Given:
n = 20
a) The possible outcome in the sample space,S, =
ⁿCₓ = ²⁰C₅
= 15504
b) probabilities of A2, A5, A4
P(A2) = ⁵C₂ / ²⁰C₂
P(A5) = ⁸C₅ / ²⁰C₅
P(A4) = ⁷C₄ / ²⁰C₄
c) No,the events A2, A5, A4, do not comstitute a partition of the sample space. i.e P(A2)+P(A5)+P(A4) ≠ 1