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Sunny_sXe [5.5K]
3 years ago
6

If a jelly bean machine contains 16 pink jelly beans, 34 blue jelly beans, 24

Mathematics
1 answer:
kiruha [24]3 years ago
5 0

Answer:

34/100

Step-by-step explanation:

Add up all the jelly beans. 16+34+24+26=100

There are 34 blue jelly beans, so the probability is 34/100 but if you want to simplify that, it would be 17/50. If you were looking for a percentage that would be 34%

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Which ones are rational and which are irrational?
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irrational, irrational, irrational, rational, rational

Step-by-step explanation:

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The length of a rectangle is 24 units. Can the perimeter x of the rectangle be 60 units when its width y is 11 units?
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No the rectangle cannot have x = 60 and y = 11 because x = 48 + 2y
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Route bought a bicycle for 1200 she later sold it for 800 what was her loss​
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To estimate a population mean, the sample size needed to provide a margin of error of 3 or less with a 95% confidence when the p
Over [174]

Answer:

The minimum sample needed to provide a margin of error of 3 or less is 52.

Step-by-step explanation:

The confidence interval for population mean (<em>μ</em>) is:

\bar x\pm z_{\alpha /2}\frac{\sigma}{\sqrt{n}}

The margin of error is:

MOE= z_{\alpha /2}\frac{\sigma}{\sqrt{n}}

<u>Given:</u>

MOE = 3

<em>σ </em>= 11

The critical value for 95% confidence interval is: z_{\alpha /2}=1.96

**Use the <em>z</em>-table for critical values.

Compute the sample size (<em>n</em>) as follows:

MOE= z_{\alpha /2}\frac{\sigma}{\sqrt{n}}\\3=1.96\times \frac{11}{\sqrt{n}}\\n=(\frac{1.96\times11}{3} )^{2}\\=51.65\\\approx52

Thus, the minimum sample needed to provide a margin of error of 3 or less is 52.

7 0
3 years ago
A stadium has 39 sections. there are 18 sections that each have 478 seats. The remaining sections each have 292 seats. If 13,528
vesna_86 [32]

Answer: 1,208 seats

Step-by-step explanation:

39-18= 21

18 x 478 = 8,604

21 x 292 = 6,132

8,604 + 6,132 = 14,736

14,736 - 13,528 = 1,208

6 0
3 years ago
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