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Lostsunrise [7]

3 years ago

15

Which equation could be represented by the number line

2 answers:

irina1246 [14]3 years ago

6 0

Answer:

0+3=3

6 + -6 =0

0 + -1 = -1

1 + -2 = -1

Lady_Fox [76]3 years ago

5 0

Answer:

A.) 0+3 = 3

B.) 6-6=0

C.) 0 - 1 = -1

D.) 1 - 2 = -1

Step-by-step explanation:

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HELP PLEASE !! <br> IS IT A, B OR C

Schach [20]

C is the answer yeah yeah

8 0

3 years ago

Sarah will buy bracelets and necklaces in order to sell them in her schools fund raising activity. The bracelets cost $2 and the

Alborosie

Answer:

The answer will be:

b ≥ 10

Step-by-step explanation:

The bracelets cost $2 and the earrings cost $3.

She needs to make at least $60.

She will need to sell more than 10 bracelets.

b = bracelets

e = earrings

2b+3e ≥ 60

6 0

3 years ago

F(x)= √x-5. find f-2

rodikova [14]

For this case we have:

Be a function of the form $y = f (x)$

Where:

$f (x) = \sqrt {x-5}$

If we want to find f (-2), we substitute $x = -2$ , then:

$f (-2) = \sqrt {-2-5}\\f (-2) = \sqrt {-7}$

Since we have a negative root, the result will be given by complex numbers. By definition:

$\sqrt {-1} = i$

So:

$f (-2) = \sqrt {7} i$

Answer:

$f (-2) = \sqrt {7} i$

3 0

4 years ago

A. Use composition to prove whether or not the functions are inverses of each other. B. Express the domain of the compositions u

Kryger [21]

Given: $f(x) = \frac{1}{x-2}$

$g(x) = \frac{2x+1}{x}$

A.)Consider

$f(g(x))= f(\frac{2x+1}{x} )$

$f(\frac{2x+1}{x} )=\frac{1}{(\frac{2x+1}{x})-2}$

$f(\frac{2x+1}{x} )=\frac{1}{\frac{2x+1-2x}{x}}$

$f(\frac{2x+1}{x} )=\frac{x}{1}$

$f(\frac{2x+1}{x} )=1$

Also,

$g(f(x))= g(\frac{1}{x-2} )$

$g(\frac{1}{x-2} )= \frac{2(\frac{1}{x-2}) +1 }{\frac{1}{x-2}}$

$g(\frac{1}{x-2} )= \frac{\frac{2+x-2}{x-2} }{\frac{1}{x-2}}$

$g(\frac{1}{x-2} )= \frac{x }{1}$

$g(\frac{1}{x-2} )= x$

Since, $f(g(x))=g(f(x))=x$

Therefore, both functions are inverses of each other.

B.

For the Composition function $f(g(x)) = f(\frac{2x+1}{x} )=x$

Since, the function $f(g(x))$ is not defined for $x=0$ .

Therefore, the domain is $(-\infty,0)\cup(0,\infty)$

For the Composition function $g(f(x)) =g(\frac{1}{x-2} )=x$

Since, the function $g(f(x))$ is not defined for $x=2$ .

Therefore, the domain is $(-\infty,2)\cup(2,\infty)$

8 0

4 years ago

Insert parenthesis to make the<br> following true.<br> 8 + 9x3 - 1 = 50

Serjik [45]

Answer:

(8+9) 3 - 1 = 50

Step-by-step explanation:

8 + 9 = 17

17 x 3 = 51

51 - 1 = 50

8 0

2 years ago

Read 2 more answers