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mixas84 [53]
1 year ago
13

6. consider neyman-pearson criteria for two cauchy distributions in one dimension assume a zero-one error loss, and for simplici

ty a2 > a1, the same "width" b, and equal priors.
Mathematics
1 answer:
il63 [147K]1 year ago
7 0

Given X and Omega, I has a one-to-one advantage versus Isobe. When B square need L F X. In part, determine the explicit integration given that the probability of X DX from minus infinity to infinity is one over Pi B. When you hold square dx, you get X minus A. multiply by B S Y One pie divided by two men plus pi divided by two plus five divided by two equals 1/5 times two multiplied by two. As a result, (u) is one. This is the answer to question B.

We're five B times 1/1 plus X here, one. Menace ai prize by the entire square multiplied by one or two. We are one Menace X -2 divided by B whole square times one or two when we are five times one. As a result, X minus one equals plus minus x minus a one. So, in this case, X equals one s squared divided by two. So one is a plus and one is a minus.

<h3>What is a dimension?</h3>

A dimension is a measurement that includes length, width, and height. When you discuss an object or location's dimensions, you're referring to its size and proportions.

Dimensions are just the different aspects of what we perceive to be reality.

We are acutely aware of the three dimensions that surround us on a daily basis: the length, width, and depth of all items in our universes, as well as the one dimension of time.

But here's the prospect that there are many more dimensions out there. According to string theory, one of the most influential physics theories of the last half-century, the universe has ten dimensions.

To learn more about dimension, visit:

brainly.com/question/13314350

#SPJ4

The complete question is:

Consider Neyman-Pearson criteria for two Cauchy distributions in one dimension

p(xlu;) i=1/πb·1/ 1 + (ₓ₋ₐ₁/b)²        i=1,2

Assume a zero one error loss and for simplicity a₂>a₁ the same "width" b and equal priors

1) Suppose the maximum acceptable error rate for classifying pattern that actually in ω₁ as if it were in ω₂ in E₁. Determine the decision boundary terms of the variables given.

2) For this boundary; what is the error rate for classifying ω₂ as ω₁?

3) What is the overall error rate under zero-one loss?

4) Apply your results to the specific case b = 1 and a₁ = -1, a₂ = 1 and E₁= 0.1.

5) Compare your result to the Bayes error rate (i.e , without the Neyman- Pearson conditions)

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Solve for w, where w is a real number.
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Answer:

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Step-by-step explanation:

\sqrt{ - 4w + 61}  = w - 4

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\boxed{(a - b)^{2}  = a^2 -2ab + b^2 }

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<u>Why </u><u>do </u><u>we </u><u>use </u><u>negative </u><u>square </u><u>root?</u>

When solving an equation such as x²= 4,

we have to consider than squaring any number removes the negative sign i.e., the result of a squared number is always positive.

In the case of x²= 4, x can be 2 or -2. Thus, whenever we introduce a square root, a '±' must be used.

However, back to our question, we did not introduce the square root so we should not consider the negative square root value.

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