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mixas84 [53]
2 years ago
13

6. consider neyman-pearson criteria for two cauchy distributions in one dimension assume a zero-one error loss, and for simplici

ty a2 > a1, the same "width" b, and equal priors.
Mathematics
1 answer:
il63 [147K]2 years ago
7 0

Given X and Omega, I has a one-to-one advantage versus Isobe. When B square need L F X. In part, determine the explicit integration given that the probability of X DX from minus infinity to infinity is one over Pi B. When you hold square dx, you get X minus A. multiply by B S Y One pie divided by two men plus pi divided by two plus five divided by two equals 1/5 times two multiplied by two. As a result, (u) is one. This is the answer to question B.

We're five B times 1/1 plus X here, one. Menace ai prize by the entire square multiplied by one or two. We are one Menace X -2 divided by B whole square times one or two when we are five times one. As a result, X minus one equals plus minus x minus a one. So, in this case, X equals one s squared divided by two. So one is a plus and one is a minus.

<h3>What is a dimension?</h3>

A dimension is a measurement that includes length, width, and height. When you discuss an object or location's dimensions, you're referring to its size and proportions.

Dimensions are just the different aspects of what we perceive to be reality.

We are acutely aware of the three dimensions that surround us on a daily basis: the length, width, and depth of all items in our universes, as well as the one dimension of time.

But here's the prospect that there are many more dimensions out there. According to string theory, one of the most influential physics theories of the last half-century, the universe has ten dimensions.

To learn more about dimension, visit:

brainly.com/question/13314350

#SPJ4

The complete question is:

Consider Neyman-Pearson criteria for two Cauchy distributions in one dimension

p(xlu;) i=1/πb·1/ 1 + (ₓ₋ₐ₁/b)²        i=1,2

Assume a zero one error loss and for simplicity a₂>a₁ the same "width" b and equal priors

1) Suppose the maximum acceptable error rate for classifying pattern that actually in ω₁ as if it were in ω₂ in E₁. Determine the decision boundary terms of the variables given.

2) For this boundary; what is the error rate for classifying ω₂ as ω₁?

3) What is the overall error rate under zero-one loss?

4) Apply your results to the specific case b = 1 and a₁ = -1, a₂ = 1 and E₁= 0.1.

5) Compare your result to the Bayes error rate (i.e , without the Neyman- Pearson conditions)

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Simplify. 3/5+(-1/4)÷7/10
melomori [17]

Answer:

1/10

Step-by-step explanation:

There are three simple fractions in this problem:  3/5, -1/4 and 7/10.  Rules of order require that the division (-1/4) divided by 7/10 be carried out first; the correct product is  -10/28, or -5/14.  Then we have 3/5 + (-5/14).

Here the LCD is 70.  Then 3/5 + (-5/14) becomes 42/70 - 35/70, which simplifies to 1/10.

5 0
3 years ago
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Estimate how many 12 inch rulers will be about the same length as a bike
navik [9.2K]

Answer:

So that means length of the bike is approx 5.7 rulers.

Step-by-step explanation:

the question says to estimate how many 12-inch rulers will be about the same length as a bike. In other words we have to measure the length of bike by in terms of ruler like 3 ruler length or 5 rular length etc.

Type of bike is not mentioned so i'm going to use bicyle.

From internet I found that approx lenght of a bike ( bicycle) is = 68 inches.

Given that 1 ruler = 12 inches

So number of rulers that can fit into 68 inches can be found by dividing 68 by 12

68/12 = 5.7

8 0
3 years ago
1. Suly watched a film that was 90 minutes long. 1/6 of the way through the film, the
AleksandrR [38]

Answer:

15 minutes

Step-by-step explanation:

Suly watched a film that was 90 minutes long. Then, she stopped at the \frac{1}{6}mark. This means that we have to find \frac{1}{6} of 90 minutes to find the amount of time Suly watched before the pizza man arrived. So therefore, the answer is 15 minutes.

Have a nice day. : )

6 0
3 years ago
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I need help on this question
storchak [24]
It’s the third one.. I think
7 0
3 years ago
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On a statistics examination the mean was 78 and the standard deviation was 10. (a) Determine the standard scores of two students
Ludmilka [50]

Answer:

a) Grade = 93, Standard score = 1.5

Grade = 62, Standard score = -1.6

b) Standard scores = 0.6, Grade = 84

Standard scores = 1.2, Grade = 90

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 78

Standard Deviation, σ = 10

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) Grade = 93

\text{Standard score } = \displaystyle\frac{93-78}{10} = 1.5

Grade = 62

\text{Standard score } = \displaystyle\frac{62-78}{10} = -1.6

b) We have to find grades of student

Standard scores = 0.6

\displaystyle\frac{x-78}{10} = 0.6\\\\x = (0.6)(10)+78 \\x = 84

Grade = 84

Standard scores = 1.2

\displaystyle\frac{x-78}{10} = 1.2\\\\x = (1.2)(10)+78 \\x = 90

Grade = 90

8 0
3 years ago
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