Paul rolls a fair dice 132 times. How many times would Paul expect to roll a three?
2 answers:
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Answer:
23 chalkboards
Step-by-step explanation:
Given:
Mean length = 5 m
Standard deviation = 0.01
Number of units ordered = 1000
Now,
The z factor =
or
The z factor =
or
Z = - 2
Now, the Probability P( length < 4.98 )
Also, From z table the p-value = 0.0228
therefore,
P( length < 4.98 ) = 0.0228
Hence, out of 1000 chalkboard ordered (0.0228 × 1000) = 23 chalkboard are likely to have lengths of under 4.98 m.
To find:
An irrational number that is greater than 10.
Solution:
Irritation number: It cannot be expression in the form of , where,
are integers.
For example: .
We know that square of 10 is 100. So, square root of any prime number is an example of an irrational number that is greater than 10.
First prime number after 100 is 101.
Required irrational number
Therefore, is an irrational number that is greater than 10.