Given that Erica and AAron,are using lottery system to decide who will wash dishes every night.
They put some red and blue power chips and draw each one. If same colour, Aaron will wash and if not same colours Erica will wash
If the game is to be fair, then both should have equal chances of opportunity for washing.
i.e. Probability for Erica washing = Prob of Aaron washing
i.e. P(different chips) = P(same colour chips)
Say there are m red colours and n blue colours.
Both are drawing at the same time.
Hence Prob (getting same colour) = (mC2+nC2)/(m+n)C2
Probfor different colour = mC1+nC1/(m+n)C2
The two would be equal is mC2 +nC2 = m+n
This is possible if mC2 =m and nC2 = n.
Or m = 2+1 =3 and n =3
That for a fair game we must have both colours to be 3.
Answer:
x = 7/9
Step-by-step explanation:
The correct answer is 15:25
So @mathmate deleted my comment because "I wasn't explaining my answer" well I did
I clearly stated that you have to make educated guess and I showed how I GOT my answer
so i guess here is my "proper" answer
There is no specific formula for this, so you can make an educated guess
for example:
13*5 = 65 (this isn't right because we need a minimum of 114)
so we continue the guessing
I then next tried
13*9
I got 117,
117 is more than 113
making 9 the minimum amount of rows for the hotel parking lot
there ya go @mathmate is that clear enough?
