Solution :
Consider quadrilateral ABCD is a parallelogram. The parallelogram have diagonals AC and DB.
So in the given quadrilateral ABCD, let the diagonal AC and diagonal DB intersects at a point E.
Thus in the quadrilateral ABCD we see that :
1. AC and DB are the diagonals of quadrilateral ABCD.
2. Angle DCE is congruent to angle BAE and angle CDE is congruent to angle ABE. (they are alternate interior angles)
3. Line DC is congruent to line AB. (opposites sides are congruent in a parallelogram )
4. Angle ABE is congruent to angle CDE. (Angle side angle)
5. Line AE is congruent to line EC. And line DE is congruent to line EB. (CPCTC)
Thus we see that if the diagonals of a 
, then the quadrilateral is a parallelogram.
Answer:
Step-by-step explanation:
The value of x is 60, as you wrote. The sum of all angles in a triangle is 180°.
The sum of all angles on a straight line is also 180°. So to find y, solve for the third angle of the triangle on the left.
50 + 60 = 110. 180-110 = 70°.
Now we know 2 of the 3 angles along the line (70° and x, 60°)
70 + 60 + y = 180
130 + y = 180
y = 50
Hope this helps. LMK if you have questions.
Answer: Hello attached below is the well written complete question
answer:
T = 40 + 30e^-0.0288t
Step-by-step explanation:
To( outside temperature ) = 40°F
T = ?
k( thermal conductivity ) = constant
A( area of heat transfer) = constant
Hence Differential equation for the temperature of the house
T = 40 + 30e^-0.0288t
Attached below is the detailed solution of the problem
