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3 years ago

8

This table shows data collected by a runner.

1 answer:

kakasveta [241]3 years ago

8 0

Answer:

its the last anwser number 4

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Find the median of the following data set. 0.48, 0.66, 1.02, 0.82, 0.7, 0.94 0.44 1.02 0.76

VLD [36.1K]

0.76 is the median.

3 0

3 years ago

Please someone help me with this!

MaRussiya [10]

The sum of two numbers and their difference is 30.

6 0

3 years ago

Solve the Differential equation (x^2 + y^2) dx + (x^2 - xy) dy = 0

natita [175]

Answer:

$\frac{y}{x}-2ln(\frac{y}{x}+1)=lnx+C$

Step-by-step explanation:

Given differential equation,

$(x^2 + y^2) dx + (x^2 - xy) dy = 0$

$\implies \frac{dy}{dx}=-\frac{x^2 + y^2}{x^2 - xy}----(1)$

Let y = vx

Differentiating with respect to x,

$\frac{dy}{dx}=v+x\frac{dv}{dx}$

From equation (1),

$v+x\frac{dv}{dx}=-\frac{x^2 + (vx)^2}{x^2 - x(vx)}$

$v+x\frac{dv}{dx}=-\frac{x^2 + v^2x^2}{x^2 - vx^2}$

$v+x\frac{dv}{dx}=-\frac{1 + v^2}{1 - v}$

$v+x\frac{dv}{dx}=\frac{1 + v^2}{v-1}$

$x\frac{dv}{dx}=\frac{1 + v^2}{v-1}-v$

$x\frac{dv}{dx}=\frac{1 + v^2-v^2+v}{v-1}$

$x\frac{dv}{dx}=\frac{v+1}{v-1}$

$\frac{v-1}{v+1}dv=\frac{1}{x}dx$

Integrating both sides,

$\int{\frac{v-1}{v+1}}dv=\int{\frac{1}{x}}dx$

$\int{\frac{v-1+1-1}{v+1}}dv=lnx + C$

$\int{1-\frac{2}{v+1}}dv=lnx + C$

$v-2ln(v+1)=lnx+C$

Now, y = vx ⇒ v = y/x

$\implies \frac{y}{x}-2ln(\frac{y}{x}+1)=lnx+C$

5 0

3 years ago

What is the measure of

Goshia [24]

60° because it's an equilateral triangle

6 0

3 years ago

163.89 to the hundreds place

saw5 [17]

Answer: 200

Explanation: 348
/ | \
Hundred | \
Tens \
Single

163.89 + 36.11 = 200
163.89 - 63.89 = 100
|
|
What is the lowest number (Not including +/- sign before it)

Answer: 1st one/36.11

<span>Final answer (what you put on paper): 100</span>

6 0

4 years ago