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Marysya12 [62]
3 years ago
15

Last month John spent 75.00 dollars on games. This month he only spent $63.00. He spent ___ percent lass this month.

Mathematics
2 answers:
miv72 [106K]3 years ago
7 0

Answer:

he spent 16% less this month

lisov135 [29]3 years ago
7 0

Answer:

First, subtract 63 from 75 to find out how much it decreased.  

75 - 63 = 12  

Divide 12 by 75.  

12 / 75 = 0.16

In percents, that is 16%.  

He spent 16% less this month.  

Hope this helps!

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Mazyrski [523]
This is just simple. For example you have a plane of the form x=a, then you just substitute x with a, and you'll get an equation with y and z only, hence you have a 2-d trace of the intersection. It is just similar for y=b and z=c.

(1) At z=1.5, 2x^2 + 5y^2 + 1.5^2 = 4 
    2x^2 + 5y^2 = 1.75
    Now you have an ellipse in the z=1.5 plane as your trace.

(2) At x=1, 2(1)^2 + 5y^2 + z^2 = 4
    5y^2 + z^2 = 2
    Now you have an ellipse in the x=1 plane as your trace.


(3) At z=0, 2x^2 + 5y^2 + (0)^2 = 4
    2x^2 + 5y^2 = 4
    Now you have an ellipse in the z=0 plane as your trace.

(4) At y=0, 2x^2 + 5(0)^2 + z^2 = 4
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    Now you have an ellipse in the y=0 plane as your trace.


5 0
4 years ago
Secant TQ and tangent TR intersect at point T. Chord SR and chord PQ intersect at point V. Find the values of x and y. If necess
san4es73 [151]

Answer:

x=4, y=9.6

Step-by-step explanation:

Using Theorem of Intersecting Secant and Tangent

TP X TQ=TR^2

9(9+12+x)=15^2\\9(21+x)=225\\189+9x=225\\9x=225-189\\9x=36\\x=4

Next, we apply Theorem of Intersecting Chords

SV X VR=PV X VQ

5 X y = x X 12

Recall: x=4

5y=4 X 12

5y=48

y=48/5=9.6

Therefore: x=4, y=9.6

4 0
3 years ago
Using first principal find the gradient of the curve whose equation is y=x^5. show working pleas​
Keith_Richards [23]

Answer:

The gradient of y = x^{5} is \frac{dy}{dx} = 5\cdot x^{4}.

Step-by-step explanation:

Geometrically speaking, the gradient of a curve is the slope of the tangent line at a given point of the curve. From perspective of Differential Calculus, the gradient is the first derivative of the curve. Let y = x^{5}, then the gradient of the curve is:

\frac{dy}{dx} = 5\cdot x^{4} (1)

The gradient of y = x^{5} is \frac{dy}{dx} = 5\cdot x^{4}.

6 0
3 years ago
Write the expression as a complex number in standard form.<br> 11i(5 + 8i)
zhuklara [117]
So We Have:

11i(5 + 8i)

We Need To Distribute.
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55 + 88i²
6 0
4 years ago
Read 2 more answers
(solve for x ) −28−1/5n=3/5n
almond37 [142]

Answer:

- 28 -  \frac{1}{5} n =  \frac{3}{5} n \\  - 28 =  \frac{1}{5} n +  \frac{3}{5} n \\  - 28 =  \frac{4}{5} n \\ n =  \frac{( - 28) \times 5}{4}  \\ n = ( - 7) \times 5 \\ \boxed{ n =  - 35}

  • <u>n=-35</u> is the right answer.

4 0
3 years ago
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